All categories

2 years ago

A rocket was launched from the ground and reached its maximum height of 36 feet at

Mathematics

1 answer:

sergeinik [125]2 years ago

4 0

This has to be figured out using a graph I don’t have one rn I’m just helping

You might be interested in

Which mixed number is equivalent to this decimal?

kogti [31]

D is correct because it is a tenth and it becomes a hundredth

4 0

3 years ago

Read 2 more answers

What is factored form of the expression 16st+15t<br>

svet-max [94.6K]

Answer:

t(16s+15)

Step-by-step explanation:

The highest common factor of 16st+15t is t.

t(16s) + t(15)

Factor.

t(16s+15)

8 0

3 years ago

Read 2 more answers

Would the sum of -13 and 20 be positive or negative? Explain your reasoning. Use complete sentences.

Debora [2.8K]

Answer:

Positive

Step-by-step explanation:

-13 plus positive 20 equals positive 7

6 0

3 years ago

18 POINTS<br><br><br> What are the 5 properties of a Parallelogram?

kap26 [50]

Answer:

There are six important properties of parallelograms I know:

Opposite sides are congruent (AB = DC).

Opposite angels are congruent (D = B).

Consecutive angles are supplementary (A + D = 180°).

If one angle is right, then all angles are right.

The diagonals of a parallelogram bisect each other

I will Add a picture of my test question wait,

6 0

3 years ago

Read 2 more answers

Would appreciate the help !

aleksandr82 [10.1K]

This is one pathway to prove the identity.

Part 1

$\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{1}{\tan(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\cot(\theta) = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)}{1-\cos(\theta)}-\frac{\cos(\theta)}{\sin(\theta)} = \frac{1}{\sin(\theta)}\\\\\frac{\sin(\theta)*\sin(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)(1-\cos(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 2

$\frac{\sin^2(\theta)}{\sin(\theta)(1-\cos(\theta))}-\frac{\cos(\theta)-\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-(\cos(\theta)-\cos^2(\theta))}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{\sin^2(\theta)-\cos(\theta)+\cos^2(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\$

Part 3

$\frac{\sin^2(\theta)+\cos^2(\theta)-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1-\cos(\theta)}{\sin(\theta)(1-\cos(\theta))} = \frac{1}{\sin(\theta)}\\\\\frac{1}{\sin(\theta)} = \frac{1}{\sin(\theta)} \ \ {\checkmark}\\\\$

As the steps above show, the goal is to get both sides be the same identical expression. You should only work with one side to transform it into the other. In this case, the left side transforms while the right side stays fixed the entire time. The general rule is that you should convert the more complicated expression into a simpler form.

We use other previously established or proven trig identities to work through the steps. For example, I used the pythagorean identity $\sin^2(\theta)+\cos^2(\theta) = 1$ in the second to last step. I broke the steps into three parts to hopefully make it more manageable.

3 0

2 years ago