Answer:
Answer = √(0.301 × 0.699 / 83) ≈ 0.050
A 68 percent confidence interval for the proportion of persons who work less than 40 hours per week is (0.251, 0.351), or equivalently (25.1%, 35.1%)
Step-by-step explanation:
√(0.301 × 0.699 / 83) ≈ 0.050
We have a large sample size of n = 83 respondents. Let p be the true proportion of persons who work less than 40 hours per week. A point estimate of p is because about 30.1 percent of the sample work less than 40 hours per week. We can estimate the standard deviation of as . A confidence interval is given by , then, a 68% confidence interval is , i.e., , i.e., (0.251, 0.351). is the value that satisfies that there is an area of 0.16 above this and under the standard normal curve.The standard error for a proportion is √(pq/n), where q=1−p.
Hope this answer helps you :)
Have a great day
Mark brainliest
Answer:
810
Step-by-step explanation:
hope it help you ☺☺....
84 is 60 % of the number 140
Answer:
(0, 4) (-4, 3) (-4, 4)
Step-by-step explanation:
Translation rules:
Units UP - Add to the y-coordinate.
Units DOWN - Subtract from the y-coordinate.
Units RIGHT - Add to the x-coordinate.
Units LEFT - Subtract from the x-coordinate.
--------------------------------------------------------------------------------------------------------------
In this case, the word problem is asking for the points after a translation of 3 units up.
(x, y+3)
(0,1) → (0,4)
(4,0) → (4,3)
(4,1) → (4,4)
--------------------------------------------------------------------------------------------------------------Now it's time to reflect the new points over the y-axis.
When reflecting over the y-axis, the y-coordinate remains the same, but the x-coordinate becomes the opposite value. (-x, y)
(0,4) → (0,4)
(4,3) → (-4,3)
(4,4) → (-4,4)
The one on the left represent 5x2 =10 and the one on the right represent 5+2=7 :)
