$e\cdot e^x -e^{-2}=-2$
$\implies e^{x+1}=e^{-2}-2$
note that RHS is negative. (because e with negative exponent is less than 1)
and LHS is always positive.
so there cannot be any solution
the answer is 54 9/14
because Divide using long division. The whole number portion will be the number of times the denominator of the original fraction divides evenly into the numerator of the original fraction, and the fraction portion of the mixed number will be the remainder of the original fraction division over the denominator of the original fraction.
Answer:
110
Step-by-step explanation:
123 + -13 = 110
I tried.
hope that helps
Answer:
1/3
Step-by-step explanation:
To get no solution, you want to get rid of x and leave an incorrect equation.
In this case, we will use 1/3x.
1/3x + 2 = 1/3x - 3
We subtract 1/3x on both sides. This will cause the 1/3x's to cancel out.
1/3x - 1/3x + 2 = 1/3x - 1/3x - 3
2 ≠ -3
As we know, 2 is not 3. Therefore, there is no solution if 1/3x is used.
Answer:
HELLO! im confused do u want us to answer all of them:D?
Step-by-step explanation:
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