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3 years ago

The sides of a quadrilateral whose sides are 85cm 143cm 165cm and 85cm and one of the diagonals is 154cm

Mathematics

1 answer:

yaroslaw [1]3 years ago

7 0

Answer:85cm is kept comstant for a while

Step-by-step explanation:

For 2nd part

1m 80 cm

=1×100cm+ 80 cm

=100cm+ 80 cm

=180cm

#According to question,

If both are added then,

=85cm+180 cm

=265cm

please brainlest

Step-by-step explanation:

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Find the smallest possible solution to 2/3x^2=24

Bezzdna [24]

$\dfrac{2}{3} x^2 = 24$

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Divide by 2/3 on both sides :
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$x^2 = 24 \div \dfrac{2}{3}$

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Change the divide fraction to multiplication fraction :
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$x^2 = 24 \times \dfrac{3}{2}$

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Simplify :
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$x^2 = 36$

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Square root both sides :
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$x = \pm \sqrt{36}$

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Answer :
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$x = \pm6$

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3 years ago

4. Divide z(5z2 - 80) by 5z (z+4)

insens350 [35]

Answer:

z-4

Step-by-step explanation:

z(5z²-80) ÷ 5z(z+4) = z-4

Step-by-step explanation:

Given: z(5z²-80) ÷ 5z(z+4)

Calculation:

First we factor numerator z(5z²-80)

Take out 5 from 5z²-80 and we get 5z(z²-16)

Now we factor 16 = 4²

5z(z²-4²)

Using formula, (a²- b²)=(a+b)(a-b)

5z(z²- 4²)⇒5z(z+4)(z-4)

Simplified fraction

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Cancel like factor from numerator and denominator

⇒ z-4

Thus, z(5z²-80) ÷ 5z(z+4) = z-4

5 0

3 years ago

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Answer:

Step-by-step explanation:

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First make the 2 fractions to one common denominator,
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