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4 years ago

The sides of a quadrilateral whose sides are 85cm 143cm 165cm and 85cm and one of the diagonals is 154cm

Mathematics

1 answer:

yaroslaw [1]4 years ago

7 0

Answer:85cm is kept comstant for a while

Step-by-step explanation:

For 2nd part

1m 80 cm

=1×100cm+ 80 cm

=100cm+ 80 cm

=180cm

#According to question,

If both are added then,

=85cm+180 cm

=265cm

please brainlest

Step-by-step explanation:

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What is the number written in standard notation?

expeople1 [14]

Answer:

option B

Step-by-step explanation:

To find the number which is written in the standard form, $5 \times {10}^{3}$

We expand ${10}^{3}$ and multiply by 5 to get

$= 5 \times (10 \times 10 \times 10)$

$=5\times 1000$

=5000

5 0

3 years ago

Read 2 more answers

textRequest reports that adults 18–24 years old send and receive 128 texts every day. Suppose we take a sample of 25–34 year old

Butoxors [25]

Testing the hypothesis, we have that:

The null hypothesis is: $H_0: \mu = 128$

The alternative hypothesis is: $H_1: \mu \neq 128$

b) The p-value of the test is of 0.1212.

c) Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

d) Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item a:

At the null hypothesis, we test if the mean is the same, that is, of 128 texts every day, hence:

$H_0: \mu = 128$

At the alternative hypothesis, we test if the mean is different, that is, different of 128 texts every day, hence:

$H_1: \mu \neq 128$

Item b:

We have the standard deviation for the population, thus, the z-distribution is used. The test statistic is given by:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

The parameters are:

$\overline{x}$ is the sample mean.

$\mu$ is the value tested at the null hypothesis.

$\sigma$ is the standard deviation of the population.

n is the sample size.

For this problem, the values of the parameters are: $\overline{x} = 118.6, \mu = 128, \sigma = 33.17, n = 30$

Hence, the value of the test statistic is:

$z = \frac{\overline{x} - \mu}{\frac{\sigma}{\sqrt{n}}}$

$z = \frac{118.6 - 128}{\frac{33.17}{\sqrt{30}}}$

$z = -1.55$

Since we have a two-tailed test, as we are testing if the mean is different of a value, the p-value is P(|z| < 1.55), which is 2 multiplied by the p-value of z = -1.55.

Looking at the z-table, z = -1.55 has a p-value of 0.0606

2(0.0606) = 0.1212

The p-value of the test is of 0.1212.

Item c:

Since the p-value of the test is of 0.1212 > 0.05, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

Item d:

Using a z-distribution calculator, the critical value for a two-tailed test with 95% confidence level is |z| = 1.96.

Since |z| = 1.55 < 1.96, we cannot conclude that the mean daily number of texts for 25–34 year olds differs from the population daily mean number of texts for 18–24 year olds.

A similar problem is given at brainly.com/question/25369247

4 0

3 years ago

Plz help I need this by tonight

miv72 [106K]

Answer:

it will take him 12 days to exercise for 576 minutes

Step-by-step explanation:

48x12=576

5 0

3 years ago

What is the value of x in the geometric sequence x,3,-1/3

GalinKa [24]

The value of the unknown variable x by virtue of the geometric sequence given in the task content is; -27.

<h3>What is a geometric sequence and what is the value of x in the sequence given?</h3>

It follows from the task content above that the variable given above is a member of the geometric sequence.

Hence, since it follows from convention that the geometric sequence in discuss has same common difference across each successive term and hence , we have;

3/x = (-1/3) ÷ 3

x = -27.

Therefore, the value of the unknown variable x by virtue of the geometric sequence given in the task content is; -27.