Please help asap!! Question from Plato assignment

What category of gymnosperms is pollinated by the snout beetle?

Andrei [34K]

Answer:

A Cycads

Explanation:

Cycads are unique among gymnosperms in that they are pollinated by insects like beetles and, in rare cases, thrips.

5 0

2 years ago

How can genetic engineering benefit the agricultural industry

dmitriy555 [2]

Answer:

Supporters of genetic engineering in agriculture point to a multitude of potential benefits of engineered crops, including increased yield, drought tolerance, reduced pesticide use, more efficient use of fertilizers, and ability to produce drugs or other useful chemicals.

4 0

3 years ago

Describe the cellular makeup and arrangement of a taste bud

Julli [10]

A taste bud is something in your body which is the way you taste food it can change over time and if you try stuff more and more then you may get start to like it

8 0

4 years ago

In humans there is a dominant allele (A) for the absence of moles; while the recessive allele (a) results in the presence of mol

Art [367]

Answer:

a. $(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. i. 0.75

ii. 0.000061

iii. 0.012

iv. 0.17

c. 0.67

Explanation:

a. The expansion of the binomial (p + q)7 would be such that:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

b. Both couples are heterozygous:

Aa x Aa

AA Aa Aa aa

Since A is dominant over a,

probability of having mole (aa) = 1/4

probability of not having moles = 3/4

Therefore, the probability of the first child not having moles = 3/4 or 0.75

ii. Let the probability of not having mole = p and the probability of having mole = q. From the binomial expansion:

$(p + q)^7$ = $p^7q^0+7p^6q+21p^5q^2+35p^4q^3+35p^3q^4+21p^2q^5+7pq^6+p^0q^7$

Probability that all of the children will have moles = $p^0q^7$

since p = 3/4 and q = 1/4

$p^0q^7$ = $(3/4)^0(1/4)^7$ = 0.000061

iii. Probability that the first two children will have no moles and the last five will have moles = $21p^2q5$

= $21(3/4)^2(1/4)^5$

= 0.012

iv. Probability that 4 will have no moles and 3 will have moles out of the 7 children = $35p^4q^3$

= $35(3/4)^4(1/4)^3$

= 0.17

c. Probability that the child born without moles is a carrier of the a-allele = probability of heterozygous.

From the cross in (b), the genotypes of those born without moles are AA and 2Aa. Therefore, the probability of not having moles and be Aa is:

= 2/3 or 0.67

8 0

3 years ago

Ryan hears a loud noise and quickly turns his eyes sideways in the direction of the sound. To accomplish this action he must use

maksim [4K]

Answer:

The correct answer is lateral rectus muscles.

Explanation:

To see what is happening in his side, or what originated the loud noise, Ryan has to use his lateral rectus muscle. Lateral rectus is one of the five extra ocular muscles that help in movement of the eye balls and help to see what is happening in and around us. It is mostly responsible for abduction, i.e. the movement of the eye balls away from the center line of the body. Defect in this muscle can result in sixth nerve palsy.

7 0

3 years ago