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Eduardwww [97]
3 years ago
6

Please Help Calculate!!!

Mathematics
1 answer:
Darina [25.2K]3 years ago
4 0

Answer:

1) 35

2) 1.51937984

Step-by-step explanation:

\frac{4/\frac{4}{7}•0.3}{2.88 ÷ 4.8}

\frac{21}{0.6}

21 ÷ 0.6

35

\frac{0.5 + \frac{1}{18}}{(1\frac{1}{6}-\frac{7}{18}}÷2.8

\frac{\frac{5}{9} }{0.36564625}

\frac{5}{9}÷0.36564625

1.51937984

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Sloan [31]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
If m(x) = x^2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?
eduard
(x^2 + 3)(5x + 9)
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7 0
3 years ago
Merta reports that 74% of its trains are on time. A check of 60 randomly selected trains shows that 38 of them arrived on time.
kenny6666 [7]

Answer:

No, the on-time rate of 74% is not correct.

Solution:

As per the question:

Sample size, n = 60

The proportion of the population, P' = 74% = 0.74

q' = 1 - 0.74 = 0.26

We need to find the probability that out of 60 trains, 38 or lesser trains arrive on time.

Now,

The proportion of the given sample, p = \frac{38}{60} = 0.634

Therefore, the probability is given by:

P(p\leq 0.634) = [\frac{p - P'}{\sqrt{\frac{P'q'}{n}}}]\leq [\frac{0.634 - 0.74}{\sqrt{\frac{0.74\times 0.26}{60}}}]

P(p\leq 0.634) = P[z\leq -1.87188]

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Therefore, Probability of the 38 or lesser trains out of 60 trains to be on time is 0.0298 or 2.98 %

Thus the on-time rate of 74% is incorrect.

6 0
3 years ago
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