All categories

3 years ago

If m(x) = x^2 + 3 and n(x) = 5x + 9, which expression is equivalent to (mn)(x)?

Mathematics

1 answer:

eduard3 years ago

7 0

(x^2 + 3)(5x + 9)
5x^3 + 9x^2 + 15x + 27

You might be interested in

A circle's circumference is approximately 44 cm.

Sav [38]

<h3>Answers</h3><h3>diameter = 14</h3><h3>radius = 7</h3><h3>area = 154</h3>

these are all approximate

======================================

Explanation:

C = pi*d is the formula for the circumference. We know that C = 44 approximately, so,

C = pi*d

d = C/pi

d = 44/3.14

d = 14.01 approximately

d = 14 also approximate

take half of this to get the radius

r = d/2 = 14/2 = 7

Then use this radius to find the circle's area

A = pi*r^2

A = 3.14*7^2

A = 153.86

A = 154 rounding to the nearest whole number

7 0

3 years ago

What is 4/5×24/12 equal to and simplified

klasskru [66]

It should be 8/5 cause 4/5 times 24/12= 4/5 times 2/1. then u multiply.

4 0

3 years ago

You are a bookkeeper, and you make $15.66 an hour. You worked 80 hours during the pay period. Anyone who makes an income is requ

monitta

You have to pay $250.56 in taxes

4 0

3 years ago

If i have a 91% in a class and i got a 78% on a test, and the test is 20% of my grade, what will my grade in the class be once t

Serggg [28]

Answer:

98%

Step-by-step explanation:

You add 78 and 20.

Tell me if it is wrong.

Thank you.

7 0

3 years ago

Read 2 more answers

For question 25 please pick 1,2,3 or 4

Juli2301 [7.4K]

Answer:

$x=\frac{2}{3} \pm \frac{1}{6}i \sqrt{158}$

Step-by-step explanation:

$18x^2-24x+87=0$

Using Quadratic Formula

$x=\frac{-b\pm \sqrt{b^2-4ac}}{2a}$

$x=\frac{-\left(-24\right)\pm \sqrt{\left(-24\right)^2-4\cdot \:18\cdot \:87}}{2\cdot \:18}$

Solving the discriminant:

$\Delta = \left(-24\right)^2-4\cdot \:18\cdot \:87\\\Delta = 576-6264\\ \Delta=-5688$

$x= \frac{24 \pm \sqrt{-5688} }{36}$

$x= \frac{24 \pm \sqrt{5688i} }{36}$

Once $\sqrt{5688} =\sqrt{2^3\cdot \:3^2\cdot \:79}=6\sqrt{158}$

$x=\frac{24\pm6\sqrt{158}i}{36}$

Dividing the denominator and numerator by 6

$x=\frac{4\pm \sqrt{158}i}{6}$

Now rewrite it:

$x=\frac{4}{6} \pm i\frac{\sqrt{158}}{6}$

$x=\frac{2}{3} \pm i \frac{\sqrt{158}}{6}$

$x=\frac{2}{3} \pm \frac{1}{6}i \sqrt{158}$

5 0

3 years ago