In particular, the following wastewater treatment processes are caried out: preliminary treatment (physical) to remove large debris and grit, primary treatment (physical) to remove settleable suspended solids, secondary treatment (biological) to remove the remaining particulates and dissolved organic material and chemical.
First, write out all combinations for the parents:
<u>SsBB</u>:
SB
sB
SB
sB
<u>ssBb</u>:
sB
sb
sB
sb
So now that you know what to put on as the x and y for the Punnett Square, set it up:
<u> | SB | sB | SB | sB </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
<u>sB | SsBB | ssBB | SsBB | ssBB </u>
<u>sb | SsBb | ssBb | SsBb | ssBb </u>
Now, listing each possible genotype and the number of times they show up in the square:
SSBB
0 times
SSBb/SSbB
0 times
SSbb
0 times
SsBB/sSBB
4 times
SsBb/SsbB/sSBb/sSbB/
4 times
Ssbb/sSbb
0 times
ssBB
4 times
ssBb/ssbB
4 times
ssbb
0 times
Since there are only 4 genotypes are possible, set up ratios of those four:
SsBB:
4 times/16 total = .25 = 25%
SsBb:
4 times/16 total = .25 = 25%
ssBB:
4 times/16 total = .25 = 25%
ssBb:
4 times/16 total = .25 = 25%
This means that the<em> genotypes</em> have a 25% : 25% : 25% : 25% likelihood.
Now, let's figure out the phenotypes of the 4 genotypes:
SsBB:
Ss = dominant
BB = dominant
SsBb:
Ss = dominant
BB = dominant
ssBB:
ss = recessive
BB = dominant
ssBb:
ss = recessive
Bb = dominant
So we have 2/4 that are S-dominant B-dominant and 2/4 that are S-recessive B-dominant.
This means that the phenotypes are:
2/4 = 50% Thin stripes with black eyes, and
2/4 = 50% Thin stripes with gray eyes.
I hope this helped you out :)
Answer:
True
Explanation:
the cerebrum controls these activities and is a part of telencephlon,forebrain