Answer:
code = 010100000001101000101
Explanation:
Steps:
The inequality yields 
, where M = 16. Therefore,
The second step will be to arrange the data bits and check the bits. This will be as follows:
Bit position number Check bits Data Bits
21 10101
20 10100
The bits are checked up to bit position 1
Thus, the code is 010100000001101000101
Answer:
See Explanation Below
Explanation:
// Program is written in C++ programming language
//.. Comments are used for explanatory purposes
// Program starts here
#include<iostream>
#include <stdlib.h>
#include <time.h>
using namespace std;
int main()
{
int computerWins = 0, computerPlay = 0;
int userWins = 0, userPlay = 0;
int tiedGames = 0;
// Computer Play
for (int play = 0; play< 10; play++) {
computerPlay = rolls();
userPlay = rolls();
// Check who wins
//Clear Screen
System("CLS")
if (computerPlay == userPlay) {
tiedGames++;
cout<<"Ties........" + tiedGames; }
else {
if (computerPlay> userPlay) {
computerWins++;
cout<<"Computer...."<< computerWins;
} else {
userWins++;
cout<<"User........"<< userWins;
}
}
}
return 0;
}
int rolls() {
srand((unsigned)time(0));
return rand() % 6 + 1;
}
Answer:
The specification is defined downwards according to the conclusions reached.
Explanation:
Real-world instances or examples of issues that do not scale well are listed following table:
- For different uses, such as solving the equation, respectively., multiplication matrices.
- It still does not scales or works well to organize a wide sequence of names or numbers as the requisite measures raise as squares by around the enlargement or increment.
Yes is the answer, Please mark as brainlest answer
