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emmasim [6.3K]
3 years ago
6

DES: Group of answer choices A) is a commonly used symmetric encryption B) algorithm that was developed in the mid-C) 1970s was

developed by a joint effort that included Microsoft refers to Date D) Electronic Security is maintained by ISO is an asymmetric algorithm
Computers and Technology
1 answer:
OLEGan [10]3 years ago
6 0

DES is a commonly used symmetric encryption

A) is a commonly used symmetric encryption

<u>Explanation:</u>

DES stands for Data Encryption Standard. It is a symmetric key algorithm and is used for encrypting electronic data. It was developed in 1975. DES is one of the oldest encryption standards to be used in the industry.

The algorithm takes 16 rounds of permutations in order to encrypt data. But now, with the advent of technology, as new algorithms have been designed and put in use, DES is less preferable.

In the process of key generation, some keys generated sometimes turn out to be weak and hence are prone to attacks. If not for the weak keys generation, DES works perfectly fine and is an effective algorithm to encrypt data.

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Develop a program that will calculate the area and perimeter of a rectangle. The length and width can be given as constant.(LENG
o-na [289]

Answer:

#include <iostream>

using namespace std;

int main()

{

 

  int length = 8;

  int width = 8;

 

  int perimeter = 2*(length + width);

  int area = length * width;

 

  cout<<"The perimeter is "<<perimeter<<endl;

  cout<<"The area is "<<area<<endl;

 

  return 0;

}

Explanation:

include the library iostream for using the input/output instructions in the c++ programming.

Create the main function and define the variable length and width with values.

Then, use the formula for calculating the perimeter and area of rectangle.

perimeter = 2*(length + width)

area = length * width

and store in the variables and finally print the output.

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Explanation:

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File Sales.java contains a Java program that prompts for and reads in the sales for each of 5 salespeople in a company. It then
myrzilka [38]

Answer:

import java.util.Scanner;

public class Sales

{

public static void main(String[] args) {

   

    int sum;

    Scanner input = new Scanner(System.in);

   

    System.out.print("Enter number of salespeople: ");

    int salespeople = input.nextInt();

    int[] sales = new int[salespeople];

       

    for (int i=0; i<sales.length; i++)

    {

     System.out.print("Enter sales for salesperson " + (i+1) + ": ");

     sales[i] = input.nextInt();

    }

    System.out.println("\nSalesperson   Sales");

    System.out.println("--------------------");

    sum = 0;

       int maxSale = sales[0];

       int minSale  = sales[0];

       int minId=1;

       int maxId=1;

    for (int i=0; i<sales.length; i++)

    {

               System.out.println("     " + (i+1) + "         " + sales[i]);

 sum += sales[i];

  if(maxSale < sales[i])

           {

               maxSale = sales[i];

               maxId = i+1;

           }

           if(minSale > sales[i])

           {

               minSale = sales[i];

               minId = i+1;

           }

   }

System.out.println("Total sales: " + sum);

       System.out.println("The average sale is: " + sum / salespeople );

       System.out.println("Salesperson "+ maxId + " had the highest sale with "+ maxSale + ".");

       System.out.println("Salesperson "+ minId + " had the lowest sale with "+ minSale + ".");

       

       int amount = 0;

       int counter = 0;

       System.out.print("Enter an amount: ");

       amount = input.nextInt();

       for (int i=0; i<sales.length; i++)

    {

     if(sales[i] > amount) {

         counter++;

         System.out.println("Salesperson "+ (i+1) + " exceeded given amount. (Number of sales: " + sales[i] +")");

     }

    }

       System.out.println("Number of salespeople exceeded given amount is: "+ counter);

}

}

Explanation:

- Ask the user for the number of salesperson

- According to entered number, create an array called sales to hold sale number for each person

- In the first for loop, assign the given sales numbers

-  In the second for loop, print all the sales people with sales, calculate the total sales. Also, find the minimum and maximum sales numbers with associated individuals.

- Print total, average, highest, and lowest sales.

- Ask user enter an amount

- In the third for loop, find the sales people who exceeded this amount.

- Print number of sales people who exceeded the amount.

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