Answer:
.
Step-by-step explanation:
To solve this problem, we need to simplify the expression
.
We know that 
Therefore:
.
Answer:
There is nothing here!
Step-by-step explanation:
I don't see anything to solve.
: )
Answer:
B
Step-by-step explanation:
the rest of the answers are the same and it is harder to compare if the lines are connected because you are most likely going to use a bar graph
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Define x :
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Let the smallest number be x.
The other two numbers will be x + 1 and x + 2.
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Construct Equation :
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Sum of these numbers is 72
⇒ x + x + 1 + x + 2 = 72
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Solve for x :
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x + x + 1 + x + 2 = 72
3x + 3 = 72
3x = 69
x = 23
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Find the numbers :
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1st number = x = 23
2nd number = x + 1 = 23 + 1 = 24
3rd number = x + 2 = 23 + 2 = 25
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Answer : The numbers are 23, 24 and 25.
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Answer:
7
Step-by-step explanation:
We want to find the number 4-digit of positive integers n such that removing the thousands digit divides the number by 9.
__
Let the thousands digit be 'd'. Then we want to find the integer solutions to ...
n -1000d = n/9
n -n/9 = 1000d . . . . . . add 1000d -n/9
8n = 9000d . . . . . . . . multiply by 9
n = 1125d . . . . . . . . . divide by 8
The values of d that will give a suitable 4-digit value of n are 1 through 7.
When d=8, n is 9000. Removing the 9 gives 0, not 1000.
When d=9, n is 10125, not a 4-digit number.
There are 7 4-digit numbers such that removing the thousands digit gives 1/9 of the number.