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horrorfan [7]
4 years ago
5

Is the probability of contamination more than twice the mean of 14.4 unusual, or can it be considered typical variation? explain

?
Mathematics
1 answer:
alexandr402 [8]4 years ago
8 0
More than the twice of the mean is 28.8 and I don't understand the meaning of typical. Seeing this porblem statement said that 3 brands had been contaminated more than twice the average, We would assume it's typical, then again it depends on what you define typical as. I think the mean is like "find the probability that a tested bar has at least twice as many insect fragments as the mean, and see if that number is really really small". 
The probability is 0.000463 and this is really small, but I really don't understand what is the meaning of typical in this problem. 
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The perimeter of a rectangle is 100 inches. If the length of the rectangle is (3x + 5) inches, and the width is (x – 9) inches.
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7 0
3 years ago
Read 2 more answers
Find the inverse function f^-1(x) for the given function f(x). f(x) =3x-8
Romashka-Z-Leto [24]
f(x)=3x-8\\\\y=3x-8\ \ \ \ |+8\\\\3x=y+8\ \ \ \ |:3\\\\x=\dfrac{y+8}{3}

Answer: y=\dfrac{x+8}{3}=\dfrac{1}{3}x+\dfrac{8}{3}

8 0
3 years ago
Please put down the steps?
e-lub [12.9K]
The answer is:  " x = 0, 1 " .
__________________________________________
Explanation:
__________________________________________
Given:
__________________________________________
   " √(x + 1)  <span>− 1 = x "  ;   Solve for "x" ;

First, let us assume that "x </span>≥ -1 "
<span>
Add "1" to EACH SIDE of the equation:

 </span>→  √(x + 1)  − 1  + 1 = x + 1  ; 

to get:  

 →  √(x + 1)  = x + 1 .

Now, "square" EACH side of the equation:

 →  [√(x + 1) ]²  = (x + 1 )² ;

to get: 

   x + 1 = (x + 1)² 

↔  (x + 1)²  = (x + 1) .


Expand the "left-hand side" of the equation:

 → (x + 1)² = (x + 1)(x +1) ;

Note: (a+b)(c+d) = ac +ad + bc + bd ;

As such:  (x + 1)(x + 1) = (x*x) + (x*1) +(1(x) + (1*1) ;
                                   =  x² + 1x + 1x + 1 ; 
                                   =  x²  + 2x  +  1 ;

Now, substitute this "expanded" value, and bring down the "right-hand side" of the equation; and rewrite the equation:
__________________________________________
   " (x + 1)² = (x + 1)(x +1) " ; 

  →  Rewrite as:  " x² + 2x + 1 = x + 1 " ;

 Subtract "x" ;  and subtract "1" ; from EACH SIDE of the equation:

               →   x² + 2x + 1 - x - 1 = x + 1 - x - 1 ; 

to get:    →   x² <span>− x = 0  

Factor out an "x" on the "left-hand side" of the equation:
___________________________________________
         </span>x² − x = x(x − 1) ;

         →  x (x − 1) = 0 ;

We have:  "x" and "(x − 1)" ; when either of these two multiplicands are equal to zero, then the "right-hand side of the equation equals "zero" .

So, one value of "x" is "0" .

The other value for "x" ;

→  x − 1 = 0 ;

Add "1" to each side of the equation:

  → x − 1 + 1 = 0 + 1 ; 

 →  x = 1 ; 
__________________________________
So, the answers:

 " x = 0, 1 " .
_________________________________

4 0
4 years ago
Which phrase describes a nonlinear function
yKpoI14uk [10]
Nonlinear has a break or is noncontinuous
For example x is not equal to 4
6 0
3 years ago
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