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Advocard [28]
3 years ago
15

At the end of the summer, liam discovers that his radiator antifreeze solution has dropped below the safe level. If the radiator

contains 4 gallons of a 25% solution, how many gallons of pure antifreeze must he add to bring it up to a desired 50% solution?
Mathematics
1 answer:
attashe74 [19]3 years ago
4 0
2 gallons 25% of 4 is 1 so there is about 1 gallon of pure in there no so adding two will make 3 gallons of antifreeze bringing total to 6 gallons 3/6 = .5 boom bam 50%
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80 POINTS, I WILL MARK BRAINLYEST, LEGIT JUST 4 QUESTIONS. PLEASE ANSWER WITH WORK OR NO POINTS FOR YOU!!!!
Korolek [52]

Answer:

see below

Step-by-step explanation:

given: size of television is height = 37 in,  length = 71 in.

A.  using Pythagorean theorem:

parts given are legs which is the sides

looking for the hypotenuse.

B.  formula:

a² + b² = c²    or   H² + L² = D²

where H = height = 37

           L = length = 71

           D = diagonal (which is req'd)

C.   D² = 37² + 71²

      D = \sqrt{1369+ 5041}

      D = \sqrt{6410}

     D = 80 in (missing length)

D. size of television:

    37 x 71 in

    Diagonal is 80 in

hope it helps and good luck!

5 0
3 years ago
The value V of a certain automobile that is t years old can be modeled by V(t) = 14,651(0.81). According to the model, when will
lakkis [162]

Answer:

a) The car will be worth $8000 after 2.9 years.

b) The car will be worth $6000 after 4.2 years.

c) The car will be worth $1000 after 12.7 years.

Step-by-step explanation:

The value of the car after t years is given by:

V(t) = 14651(0.81)^{t}

According to the model, when will the car be worth V(t)?

We have to find t for the given value of V(t). So

V(t) = 14651(0.81)^{t}

(0.81)^t = \frac{V(t)}{14651}

\log{(0.81)^{t}} = \log{(\frac{V(t)}{14651})}

t\log{(0.81)} = \log{(\frac{V(t)}{14651})}

t = \frac{\log{(\frac{V(t)}{14651})}}{\log{0.81}}

(a) $8000

V(t) = 8000

t = \frac{\log{(\frac{8000}{14651})}}{\log{0.81}} = 2.9

The car will be worth $8000 after 2.9 years.

(b) $6000

V(t) = 6000

t = \frac{\log{(\frac{6000}{14651})}}{\log{0.81}} = 4.2

The car will be worth $6000 after 4.2 years.

(c) $1000

V(t) = 1000

t = \frac{\log{(\frac{1000}{14651})}}{\log{0.81}} = 12.7

The car will be worth $1000 after 12.7 years.

5 0
3 years ago
Can someone help me please it’s urgent
laila [671]

Answer:

use the x and y method and try to apply it with the 3 given expressions

7 0
3 years ago
Write a number y divided by 6 as an expression.
Alina [70]

Answer:

y ÷ 6.

Step-by-step explanation:

An expression is a combination of a number(s) and a variable.

Here, we simply need to write the expression from the word problem in mathematical form.

"Number" is unknown.

Variables are used to represent an unknown value.

(The variable in this expression is y).

The word problem says a number y divided by 6.

This simply means: y ÷ 6.

7 0
3 years ago
1) 2/7×1/2 <br>2) 5/8×4/5 <br>3) 1/6×2/3<br>4) 1/3×3/4<br>5) 1/2×2/3<br>6) 1/3×2/5​
nignag [31]
1) 1/7
2) 1/2
3) 1/9
4) 1/4
5) 1/3
6) 2/15
hope this helped:)
5 0
3 years ago
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