M = 3
Is that what you were looking for?
I believe it’s C because the original coordinates where (1, -3) all you will have to do it’s subtract -6 by 1 and add 2 and -3
Answer:
52488y²
Step-by-step explanation:
first solve for 3³. then solve for 18²
3³=27
18²=324
27*324=8748
then multiply 8748 by 6y²
=52488y^2
Answer:
H0: μ = 5 versus Ha: μ < 5.
Step-by-step explanation:
Given:
μ = true average radioactivity level(picocuries per liter)
5 pCi/L = dividing line between safe and unsafe water
The recommended test here is to test the null hypothesis, H0: μ = 5 against the alternative hypothesis Ha: μ < 5.
A type I error, is an error where the null hypothesis, H0 is rejected when it is true.
We know type I error can be controlled, so safer option which is to test H0: μ = 5 vs Ha: μ < 5 is recommended.
Here, a type I error involves declaring the water is safe when it is not safe. A test which ensures that this error is highly unlikely is desirable because this is a very serious error. We prefer that the most serious error be a type I error because it can be explicitly controlled.
