Answer: C. 12
Step-by-step explanation:
You ca also use sss, sas, asa, aas, and that, hl.
Answer:
exponential function going through point 0, negative 2 and ending down on the right
Step-by-step explanation:
(Took the test, also seen as "Option A", this graph goes down and hits the y line at 0,-2.)
u = 1+3e<span>-x</span>
so that (Don't forget to use the chain rule on e<span>-x</span>.)
du = 3e<span>-x</span>(-1) dx = -3e<span>-x</span> dx ,
or
(-1/3)du = e<span>-x</span> dx .
However, how can we replace the term e<span>-3x</span> in the original problem ? Note that
.
From the u-substitution
u = 1+3e<span>-x</span> ,
we can "back substitute" with
e<span>-x</span> = (1/3)(u-1) .
Substitute into the original problem, replacing all forms of x, getting
(Recall that (AB)C = AC BC .)
The area of the triangle and the square are 4.66( infinite)