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3 years ago

FINAL ROUND FOR THE MATHEMATICS RACE....

Mathematics

2 answers:

Stolb23 [73]3 years ago

8 0

Answer:

29/3

Step-by-step explanation:

You use PEMDAS and do the parentheses first:

(5+24)/3= 29/3

madam [21]3 years ago

6 0

Answer:

29/3

or 9.6666666666666666666666666

Step-by-step explanation:

5+24= 29

then divide by 3

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I need the perimeter and area

kirza4 [7]

Answer:

P: 32

A: 63

Step-by-step explanation:

I hope that thats right..

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3 years ago

Christian is planning a vacation and finds an airplane ticket that cost 180$. He found a promo code offering 17% off. Write a si

lesya [120]

Answer:

83/100 x 180

Step-by-step explanation:

We have to find the cost of the ticket after the discount.

100% - 17%= 83%

83% of the total percentage of the original price that he needs to pay.

So we do:

83/100 x 180

So, this would be the expression.

Hope this helps!:)

7 0

3 years ago

A circus tent is cylindrical upto a height of 3.3 m and conical above it if the diameter of the base is 100m and slant height of

Rina8888 [55]

Total cost of canvas required in making the tent is rupees 79128

Solution:

Given:

Height of the cylindrical tent = h = 3.3 m

Diameter of it's base = d = 100m

$radius = \frac{diameter}{2} = \frac{100}{2} = 50$

r = 50 m

Curved surface area of cylinder:

$C.S.A = 2 \pi rh$

$C.S.A = 2 \times 3.14 \times 50 \times 3.3 = 1036.2$

Thus Curved surface area of cylinder = 1036.2 square meter

Curved surface area of cone:

$C.S.A = \pi rl$

$C.S.A = 3.14 \times 50 \times 56.4 = 8854.8$

Thus Curved surface area of cone = 8854.8 square meter

Total curved area of tent:

⇒ curved area of cone + curved area of cylinder

$\rightarrow 8854.8 + 1036.2=9891$

Thus total curved area of tent = 9891 square meter

find total cost of canvas required in making the tent:

The cost of canvas is 8 rupees per square meter

$\rightarrow \text{total cost } = 9891 \times 8 = 79128$

Thus total cost of canvas required in making the tent is rupees 79128

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3 years ago

Line L1, L2 and L3 are in the same plane, L1 is perpendicular to L2, and L3 is parallel to L1. which of the following statement

exis [7]

Only Statement 2 is surely correct.
because there maybe chances that the line L1 and L3 lies above the line L2 and they can also fulfill the condition of perpendicularity so we can't be sure about statement 3 & statement 1 is clearly incorrect

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3 years ago

The ordered pair (−3,−6) is a solution for the first equation, and it is a solution for the second equation. Therefore, (−3,−6)

Alisiya [41]

False. If x=-3 and y=-6 and you substitute them into the equation they do not add up

7 0

3 years ago

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