The answer is 177.57 please mark me as brainliest since I'm first to answer, thanks,~Kashout kam
Answer:
Step-by-step explanation:
We would set up the hypothesis test. This is a test of a single population mean since we are dealing with mean
For the null hypothesis,
µ = 152.5
For the alternative hypothesis,
µ ≠ 152.5
This is a two tailed test.
Since no population standard deviation is given, the distribution is a student's t.
Since n = 231
Degrees of freedom, df = n - 1 = 231 - 1 = 230
t = (x - µ)/(s/√n)
Where
x = sample mean = 148.9
µ = population mean = 152.5
s = samples standard deviation = 27.4
t = (148.9 - 152.5)/(27.4/√231) = - 2
We would determine the p value using the t test calculator. It becomes
p = 0.047
Since alpha, 0.05 > thanthere sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals the p value, 0.047, then we would reject the null hypothesis. Therefore, At a 5% level of significance, there is sufficient evidence to conclude that the self-efficacy of adults who have experienced childhood trauma differs from that in the general population of individuals
Hundreds tens and ones 1 and 1 and 8
The Ratio would be 43:100.
Lets simplify the problem,
Expected increase of nurses = 711900
Expected increase of physicians = 168300
Ratio = Expected increase of nurses / Expected increase of physicians
Ratio = 711900 / 168300
= 43/100
Ratio = 43:100
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Ax3 + bx2 + cx + d = 0 where a 6= 0
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