Answer:
Explanation:
Answer:
Explanation:
Answer:
Explanation:
In a the card game there are 4 groups N,E,W,S. Each group consist of 13 cards each
N: A,K,Q,J,10,9,8,7,6,5,4,3,2
E: A,K,Q,J,10,9,8,7,6,5,4,3,2
W: A,K,Q,J,10,9,8,7,6,5,4,3,2
S: A,K,Q,J,10,9,8,7,6,5,4,3,2
a) The number of ways player 1 receives 4 aces
Since 52 cards can be arranged in 52! ways
An A's card can be arranged in 4! ways
Number of possible arrangement of A's cards among the 4 player =( 52! / 4! )
So for 1 player to receive all the Ace's there will be (13!/4!) ways
13!/4! = 259459200 ways
b) each player receive 13cards of the same suit
There are 4! different ways to deal the cards so that each player gets all the cards of one suit.
The distribute 4 objects (suits) to the 4 players.
The number of ways to deal out the cards is (52!/13!) X (39!/13!) X (26! / 13!) X (13!/13!). You choose 13 cards to give to the first player, 13 to the second, 13 to the third and 13 to the fourth.
Using the rule for probability, you get an answer of
4! / ((52!/13!) X (39!/13!) X (26! / 13!) X (13!/13!))
