Question

How many moles of potassium hydroxide are needed to completely react with 2.94 moles of aluminum sulfate according to the following equation:

Answer 1

Answer:- Third choice is correct, 17.6 moles

Solution:- The given balanced equation is:

$Al_2(SO_4)_3+6KOH\rightarrow 2Al(OH)_3+3K_2SO_4$

We are asked to calculate the moles of potassium hydroxide needed to completely react with 2.94 moles of aluminium sulfate.

From the balanced equation, there is 1:6 mol ratio between aluminium sulfate and potassium hydroxide.

It is a simple mole to mole conversion problem. We solve it using dimensional set up as:

$2.94molAl_2(SO_4)_3(\frac{6molKOH}{1molAl_2(SO_4)_3})$

= 17.6 mol KOH

So, Third choice is correct, 17.6 moles of potassium hydroxide are required to react with 2.94 moles of aluminium sulfate.