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stira [4]
4 years ago
11

Which of the following reactions would have the smallest value of K at 298 K? Which of the following reactions would have the sm

allest value of K at 298 K? A + B → 2 C; E°cell = -0.030 V A + 2 B → C; E°cell = +0.98 V A + B → C; E°cell = +1.22 V A + B → 3 C; E°cell = +0.15 V More information is needed to determine.
Chemistry
1 answer:
Firdavs [7]4 years ago
7 0

Answer:

The reaction with smallest value of K is :

A + B → 2 C; E°cell = -0.030 V

Explanation:

nFE^o_{cell}=RT\ln K

where :

n = number of electrons transferred

F = Faraday's constant = 96500 C

E^o_{cell} = standard electrode potential of the cell

R = Gas constant = 8.314 J/K.mol

T = temperature of the reaction = 25^oC=[273+25]=298K

K = equilibrium constant of the reaction

As we cans see, that standard electrode potential of the cell is directly linked to the equilibrium constant of the reaction.

  • Higher E^o_{cell} higher will be the value of K.
  • Lower E^o_{cell} lower will be the value of K.

So, the reaction with smallest value of electrode potential will have smallest value of equilibrium constant. And that reaction is:

A + B → 2 C; E^o_{cell} =-0.030 V

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fomenos
1st half-life: 100%/2 = 50%
2nd half-life: 50%/2 = 25% + 50% (from first half-life)
3rd half-life: 25%/2 = 12.5% + 75% (from first and second half-lives

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3 0
3 years ago
A coyote and an oak tree both reproduce ?
Irina18 [472]

Answer:

<h2>YES</h2>

Explanation:

Coyotes and oak trees are multicellular organisms and multicellular organisms reproduce asexually and sexually.

Many multicellular lower plants give off asexual spores, either aerial or motile and aquatic (zoospores), which may be uninucleate or multinucleate.

4 0
3 years ago
what is the ph of a 1.8 m solution of a weak acid ha, with a ka of 9.55×10−10? the equilibrium expression is: ha(aq) h2o(l)⇋h3o
sesenic [268]

The pH of the solution is 4.38.

<h3>What is the pH?</h3>

The first thing that we must do is to set up the ICE table for the reaction as shown;

Given that;

HA = 1.8 M

        HA(aq) + H2O(l) ⇔ H3O^+(aq) + A^-(aq)

I         1.8                                  0                0

C         - x                                 +x                +x

E       1.8 - x                                  x                  x

K = [H3O^+] [A^-]/[HA]

9.55 × 10^−10 = x^2/0.0158 - x

9.55 × 10^−10(1.8 - x ) = x^2

1.719 * 10^-9 - 9.55 * 10^-10x = x^2

x^2 + 9.55 * 10^-10x - 1.719 * 10^-9 = 0

x=0.000041 M

pH = -log(0.000041 M)

pH = 4.38

Learn more about pH:brainly.com/question/15289741

#SPJ1

8 0
2 years ago
How many atoms of gold are in a pure gold coin weighing 12.0g?
grigory [225]
12.0g x 1 mol / 63.546g = 0.188839581mol 

<span>So, for every 1 mole, we have 6.022 x 10^23 of whatever we're measuring. This gives us a conversion factor of (1 mole / 6.022 x 10^23 atoms) or (6.022 x 10^23 atoms / 1 mole).
</span>
0.188839581 mol x (6.022 x 10^23 atoms) / 1 mol = 1.137191955 x 10^23 

<span>Remember from before that we are limited to 3 significant figures. Since our calculations are complete, we can now round down to: 1.14 x 10^23 </span>

<span>That should be your answer!

Hope it helps!
xo</span>
3 0
3 years ago
Why is water essential to living things? (1 pc
DIA [1.3K]

Answer:

Living organisms need water to survive. Many scientists even believe that if any extra-terrestrial exists, water must be present in their environments. All oxygen-dependent organisms need water to aid in the respiration process. Some organisms, such as fish, can only breathe in water. Other organisms require water to break down food molecules or generate energy during the respiration process. Water also helps many organisms regulate metabolism and dissolves compounds going into or out of the body.

Explanation:

6 0
3 years ago
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