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charle [14.2K]
3 years ago
5

Terry bought a gold necklace at a pawnshop and was wondering if it was “real” gold. She decided to perform a density test. She p

laced the necklace in a graduated cylinder of water that had 47.00 mL of water and the water rose to 48.35 mL. She then weighed the necklace and found it to have a mass of 22.89 g. What is the density of Terry’s necklace?
Chemistry
1 answer:
Virty [35]3 years ago
8 0

Answer:

d = 16.96 g/mL

Explanation:

Given that,

Initial water level in graduated cylinder is 47 mL and final water level is 48.35 mL.

The weight of the neclace is 22.89 g.\

We need to find the volume of the necklace. We know that, density equals mass per unit volume. So,

d=\dfrac{m}{V_f-V_i}\\\\d=\dfrac{22.89\ g}{(48.35-47)\ mL}\\\\d=16.96\ g/mL'

Hence, the density of Terry’s necklace is 16.96 g/mL.

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7. Given a 32.0 g sample of methane gas (CH), determine the pressure that would be exerted on a container with
pishuonlain [190]

Answer:

P = 58.52 atm

Explanation:

Given data:

Mass of sample = 32.0 g

Pressure of sample = ?

Volume of gas = 850 cm³

Temperature of gas = 30°C

Solution:

Number of moles of gas:

Number of moles = mass/molar mass

Number of moles = 32.0 g/ 16 g/mol

Number of moles = 2 mol

Pressure of gas:

PV = nRT

P= Pressure

V = volume

n = number of moles

R = general gas constant = 0.0821 atm.L/ mol.K  

T = temperature in kelvin

Now we will convert the temperature.

30+273 = 303 K

850 cm³ × 1L /1000 cm³ = 0.85 L

by putting values,

P× 0.85 L = 2 mol × 0.0821 atm.L/ mol.K  × 303 K

P = 49.75 atm.L/ 0.85 L

P = 58.52 atm

5 0
3 years ago
PLS HELP ASAP NO LINKS
Elina [12.6K]

Answer:

.biology and maybe physics

3 0
3 years ago
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I need help pls I will give you brainlist
White raven [17]

Answer:

I think it is the second one

Explanation:

Because what the cold water did to the table salt, is that it separated its molecules dissolving the salt.

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5 0
3 years ago
Label each statement below as either describing the limit of detection (LOD) or the limit of quantitation (LOQ
Orlov [11]

Answer:

It is the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy - LOQ

The concentration is equal to three times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOD

The concentration is equal to 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve - LOQ

It is the minimum amount of analyte that produces a signal that is significantly different from the blank - LOD

Explanation:

We define the limit of detection has the lowest amount of analyte that produces a signal that is significantly different from a blank solution ( the absence of the substance). It is calculated as three times the standard deviation of the signal from the blank divided by the slope of the calibration curve.

The limit of quantitation (LOQ) is defined as the minimum amount of analyte that produces a signal which can be measured with reasonable accuracy. It is measured as 10 times the standard deviation of the signal from the blank divided by the slope of the calibration curve.

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Question 14 (5 points)
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