Integration will be ln | ( x /9 ) + ( 
) | + c .
Given ∫ 1 dx / ( 
- 81 )
Put ,
x = 9 secθ
dx = 9 secθ tanθ dθ
and
= 9 tanθ
Substituting values in ∫ 1 dx / ( - 81 ) ,
∫ (9 secθ tanθ ) dθ / ( 9 tanθ )
∫ secθ dθ = ln | secθ + tanθ | + c
= ln | ( x /9 ) + ( / 9 ) | + c
= ln | ( x /9 ) + ( ) | + c
Hence , the integration will be ln | ( x /9 ) + ( ) | + c .
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40c=520
This is the proper equation because there are 40 quarters in $10. Thus, if we could only fit $10 worth of quarters in each wrapper, we can only fit 40quarters in each wrapper. C represents the amount of wrappers we will need.
Hope this helps!
If you divide 55 by 11 you get 5. You then divide 30 by 5 too and you get x=6
Answer and Step by step exploration
y=5x^2-30x+95=5x^2-30x+45+50=5(x^2-6x+9)+50= (x-3)^2+50
