Answer:
0.589
Step-by-step explanation:
THis is a conditional probability question. Let's look at the formula first:
P (A | B) = P(A∩B)/P(B)
" | " means "given that".
So, it means, the <u><em>"Probabilty A given that B is equal to Probability A intersection B divided by probability of B."</em></u>
<u><em /></u>
So we want to know P (Female | Undergraduate ). This in formula is:
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
Now,
P (Female ∩ Undergraduate) means what is common in both female and undergraduate? There are 43% female that are undergrads. Hence,
P (Female ∩ Undergraduate) = 0.43
Also,
P (Undergraduate) is how many undergrads are there? There are 73% undergrads, so that is P (undergraduate) = 0.73
<em>plugging into the formula we get:</em>
P (Female | Undergraduate) = P (Female ∩ Undergraduate)/P(Undergraduate)
=0.43/0.73 = 0.589
this is the answer.
Answer:
A = 615.75
cost = $107.08
Step-by-step explanation:
the training area = (28/2)^2*pi
training area = 615.75 square feet
615.75/5.75 = 107.08
$107.08
Answer:
yes
Step-by-step explanation:
if it ends at 430 he will have 30 min before his appoionment
Answer:
a. 81.5%
Step-by-step explanation:
The z-score for 400 is ...
Z = (X -μ)/σ = (400 -500)/100 = -1
The z-score for 700 is ...
Z = (700 -500)/100 = 2
The empirical rule tells you that 68% of the distribution is within ±1σ of the mean, and 95% is within ±2σ of the mean. Half of that first number is in the range Z = -1 to 0, and half that second number is in the range Z = 0 to +2. So, the probability you want is ...
(1/2)(68%) + (1/2)(95%) = 81.5% . . . . matches choice A

- Given - <u>an </u><u>equation </u><u>in </u><u>it's</u><u> </u><u>general </u><u>form</u>
- To do - <u>convert </u><u>the </u><u>given</u><u> </u><u>equation</u><u> </u><u>into </u><u>a </u><u>form </u><u>that </u><u>is </u><u>easy </u><u>to </u><u>solve</u>
<u>Given </u><u>equation</u><u> </u><u>-</u>

<u>solve </u><u>the </u><u>parenthesis </u><u>so </u><u>as </u><u>to </u><u>obtain </u><u>simpler </u><u>terms</u>

<u>solve </u><u>the </u><u>like </u><u>terms </u><u>and </u><u>you'll</u><u> </u><u>obtain </u><u>the </u><u>required</u><u> </u><u>equation</u><u> </u><u>!</u>

hope helpful ~