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2 years ago

How does sugar dissolve in water ? & Read Carefully ?

1 answer:

8 0

Depends

such as if the molecule in the water is hot then the molecules of the sugar would dissolve faster since the hot water speeds the process.

Cold water molecules would be slower since of course its slows down the reaction when sugar is applied.

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Wanda manages an application that fluctuates in usage quite a bit. Sometimes it uses quite a few servers with lots of memory and

TEA [102]

Answer:

c. Elasticity

Explanation:

When referring to Cloud Servers this capability is known as Elasticity. It basically describes how able and efficient a server is to automatically implement resources and remove resources in order meet the specific amount of demand at any given moment. Many times a server will not have much demand but will still have all the resources being used by the server. Being able to remove these unused resources so that they are available for other usage is what makes the servers elastic.

8 0

2 years ago

In the late 1980s, which wide area network (wan) technology became one of the standard methods of connecting business computers

Paha777 [63]

Frame i think, thats what i learned about

7 0

3 years ago

What are the modes of operation of WLANs?

Nimfa-mama [501]

Answer:

WLAN's or Wireless LAN Units have 2 main modes of operation

Explanation:

The Two Main modes of Operation are the following

<u>Infrastructure Mode:</u> in this mode the main WLAN unit becomes the main connection point in which all devices are connected to and the main unit provides an internet connection to all the devices connected to it.

<u>Ad Hoc Mode:</u> in this mode devices transfer data from one another back and forth without permission from a base unit.

Some WLAN units will also include 2 extra modes of operation called Bridge and Wireless Distribution System (WDS).

<u>Bridge Mode:</u> this mode allows the base unit to act as an intermediary and bridge two different connection points. Such as bridging a wired connection with a wireless one.

<u>WDS Mode:</u> this mode uses various access points to wirelessly interconnect devices to the internet using repeaters to transmit connections. It can provide internet to both wired and wireless clients.

I hope this answered your question. If you have any more questions feel free to ask away at Brainly.

6 0

3 years ago

8. What is the order of growth execution time of the push operation when using the LinkedStack class, assuming a stack size of N

velikii [3]

The order of growth execution time of the push operation when using the LinkedStack class, assuming a stack size of N is; O(1)

<h3>Understanding Computer Programming Language</h3>

Let Top be the position of last element inserted in Array.

For Push operation, the process is as follows;

if(Top == last index of Array) {

Printf(“Stack Overflow”)

} else {

Top = Top + 1

a[Top] = element you want to insert

}

Read more about Computer Programming at; brainly.com/question/22654163

8 0

1 year ago

More registers appear to be a good thing, in terms of reducing the total number of memory accesses a program might require. Give

gulaghasi [49]

Answer:

Following is given the answer step by step:

Explanation:

First of all we will write a program using MARIE that will support the statement: Sum = (A + B) - (C + D). All the necessary comments are given in front of each statement:

Load A # variable A will be loaded

Add B # B will be added to A

Store Temp1 # A + B will be stored in Temp1

Load C # C will be loaded in memory

Add D # D will be added to C

Store Temp2 # C + D will ge stored in Temp2

Load Temp1 # Temp1 will be loaded in the memory

Subt Temp2 # Temp2(A + B) get subtracted from Temp1(A - B)

Store Sum # (A + B) - (C + D) will get stored in Sum.

We can see from above program that memory is accessed 9 times. While if C + D get executed first than memory accesses will be reduced to 7.

Above same program could be written using an architecture of 4 registers:

The program is as follows:

Load R1 , A #A will be loaded into R1

Load R2 , B # B will be loaded into R2

Add R1 , R2 # R2 gets added to R1 and the result is stored in R1 (A + B)

Load R3 , C # C loaded into R3

Load R4 , D # D loaded into R4

Add R3 , R4 # Value in R4 gets added into R3 and R3 becomes (C + D)

#no memory accesses required for this operation

Subt R1 , R4 #R4 (C + D) gets subtracted from R1 (A + B)

#no memory accesses required for this operation

Store Sum # The recent value will be stored into Sum

Here memory is accessed 5 times in total.

8 0

2 years ago