Answer:
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
Step-by-step explanation:
For n=6 the degrees of freedom will be n-1 = 5 .
The goodness of fitness test χ²with significance of level ∝= 0.05 and 5 degrees of freedom is 11.07 (One tailed test )
The critical region depends on ∝ and the alternative hypothesis
a) When Ha is σ²≠σ² the critical region is
χ² < χ²(1-∝/2)(n-1) and χ² > χ²(1-∝/2)(n-1) Two tailed test
( χ² < 0.83) and ( χ² > 0.83)
b) When Ha is σ²> σ² the critical region falls in the right tail and its value is
χ² > χ²(∝)(n-1) One tailed test {11.07 (One tailed test )}
c) When Ha is σ² <σ² the critical region will be entirely in the left tail with critical value
χ²(1-∝)(n-1) One tailed test (1.145)
An inequality to model this would be
7x + 8y ≥ 336.
We multiply the number of minutes running, x, by the number of calories burned each minute by running, 7. We multiply the number of minutes swimming, y, by the number of calories burned each minute by swimming, 8. Adding these together, it needs to be greater than or equal to 336, since she wants to burn at least that many calories.
Julia’s score is <em>y</em> and Tina’s score is <em>y</em> + 6.
Step-by-step explanation:
Let us take Julia’s score be <em>y</em>.
First Tina scored 4 points more than Julia, so the expression is <em>y</em> + 4.
Then, Tina earned 2 points as extra credic, now the expression becomes
(y + 4) + 2 = y + 6.
Hence Julia’s score is <em>y </em>and Tina’s score is <em>y</em> + 6.
Answer:
Step-by-step explanation:
<u><em>Formulate the equation of the polynomial function</em></u>
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<em>I hope this helps you</em>
<em>:)</em>
We need to work out first the scale factor of the side length
Side MN correspond to the side JK
Side MN = 3.5 cm
Side JK = 14 cm
Scale factor = 14/3.5 = 4
Side OM correspond to side LJ
Side OM = 12 cm
Side LJ = 12 × 4 = 48 cm
