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alisha [4.7K]
2 years ago
6

A frog is at the bottom of a 30 meter well. each day he summons enough energy for one 3 meter leap up the well. exhausted, he th

e hangs there for the rest of the day. at night, while he is asleep, he slips 2 meters backwards. how many days does it take him to escape the well?
note: assume after the first leap that his hind legs are exactly 3 meters up the well. his hind legs must clear the well for him to escape.
Mathematics
1 answer:
Hatshy [7]2 years ago
8 0

Answer:

It takes 30 days

Step-by-step explanation:

Think about it. The frog jumps 3 meters and the slides 2 meters down while in his sleep. So each day he only moves up one because 3-2=1. 30/1 is 30, therefore the answer is 30 days.

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Answer:

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M∠1 = 80 – x; and
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10

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3 years ago
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Answer:

\displaystyle D)  {x}^{5}  +  \rm C

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2 years ago
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The complete question is added as an attachment

From the attached figure, the product expression is:

2√8x³(3√10x⁴ - x√5x²)

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Open the bracket

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