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alisha [4.7K]
3 years ago
6

A frog is at the bottom of a 30 meter well. each day he summons enough energy for one 3 meter leap up the well. exhausted, he th

e hangs there for the rest of the day. at night, while he is asleep, he slips 2 meters backwards. how many days does it take him to escape the well?
note: assume after the first leap that his hind legs are exactly 3 meters up the well. his hind legs must clear the well for him to escape.
Mathematics
1 answer:
Hatshy [7]3 years ago
8 0

Answer:

It takes 30 days

Step-by-step explanation:

Think about it. The frog jumps 3 meters and the slides 2 meters down while in his sleep. So each day he only moves up one because 3-2=1. 30/1 is 30, therefore the answer is 30 days.

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Follow PEMDAS in reverse to undo what's happening to x.

We first add 1 to both sides, then divide both sides by 5 to fully isolate x.

Refer to the steps below to see what I mean.

-1 + 5x \ge -16\\\\5x \ge -16+1\\\\5x \ge -15\\\\x \ge -15/5\\\\x \ge -3\\\\

The inequality sign stays the same the entire time. The only time it flips is when you divide both sides by a negative number.

The solution set for x is anything -3 or larger.

If x was an integer, then we could say the solution set is {-3, -2, -1, 0, 1, 2, 3, 4, 5, 6, ...}

7 0
2 years ago
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3 years ago
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