Answer:
$367,500
Explanation:
Estimation of the family’s life insurance needs
Using the easy method
Based on the information given we were told that Mark gross salary is $75,000 while is wife
Parveen is a stay-at-home mom this means that we would be using the easy method to estimate the family’s life insurance needs based on Mark gross salary of $75,000 because he is the only one that earn on a monthly basis.
Insurance need =$75,000 x 7 years x 70%
Insurance need = $367,500
Therefore the family’s life insurance needs will be $367,500
Depends on what you are trying to fix
Answer:
The total loss in welfare to the economy will be -$32.
Explanation:
By intersecting the supply function QS to the demand function QD, we will find the equilibrium price:
QD = QS
16P - 8 = 64 - 16P
16P + 16P = 64 +8 =
32P = 72
P = $2.00
Replacing the equilibrium price either in QS or QD, we foind the equilibrium quantity:
QS = 64 - 16*2 = 64 -32
QS = 32
In this case the total revenues at the equilibrium price RE will be:
RE = 32 * $2 = $64
On the other hand if the government imposes a price floor at $3.00, then the new total revenues RN will be:
RN = 32 * $3 = $96
Therefore the total losses is find by subtracting the revenue at the goverment price floor RN to the revenue at the equilibrium price RE:
LT = RE - RN
LT = $64 - $96 = -$32
Store equipment will increase
Answer:
The mean withdraw has increased during weekend.
Explanation:
Assume that the withdraw amounts are normal distributed. To test whether the mean withdrawal has increased during weekends, we take a z-test. The z-test is possible because the observed sample (weekend transactions) is greater than 30.
The null hypothesis (
) is when the mean withdrawal is greater than 550. The alternative hypothesis (
) is when the mean withdrawal is equal to 550 or smaller. At an alpha of 0.05% is selected with a two-tailed test, , there is 0.025% of the samples in each tail, and the alpha has a critical value of 1.96 or -1.96. If the z-value is greater than 1.96 or less than -1.96, the null hypothesis is rejected.
z-value = (600-550) / 70 / 36^(1/2) = 0.1190
At α=0.05, the z-value < 1.96 and > -1.96, the null hypothesis is not rejected. Therefore, the mean withdraw has increased during weekend.
