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3 years ago

5

Barry needs to find the area of a rectangular room with a length that is 2 feet longer than the width. Write an expression for t

he area of the rectangle in terms of the width.

1 answer:

babunello [35]3 years ago

5 0

Answer:

try asking a master, ok?

Step-by-step explanation:

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Which 37/99 as a decimal <br> A) 0.037<br> B) 0.37<br> C) 0.37<br> D) 3.73

ladessa [460]

Answer:

b

Step-by-step explanation:

3 0

2 years ago

Read 2 more answers

Which of the following sine values is the lowest<br><br> Sin(82)<br> Sin(3)<br> Sin(78)<br> Sin(15)

MaRussiya [10]

The answer is either Sin 3 or sin 82

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3 years ago

I need help with all three questions please. I am just Stuck.

vitfil [10]

Answer:

$p_{o} = 6$ , $r = 2$ , $p_{12} = 24576$ .

Step-by-step explanation:

The value of $p_{o}$ is the first value of the geometric series, that is, $p_{o} = 6$ .

If the series represents a geometric sequence, then $r$ must be constant for every consecutive pair of elements, that is:

$r_{1} = \frac{p_{1}}{p_{o}} = \frac{12}{6} = 2$

$r_{2} = \frac{p_{2}}{p_{1}} = \frac{24}{12} = 2$

$r_{3} = \frac{p_{3}}{p_{2}} = \frac{48}{24} = 2$

Since $r_{1} = r_{2} = r_{3} = 2$ , $r = 2$ .

The geometric sequence can be represented by the following formula:

$p_{n} = p_{o}\cdot r^{n}$ , for $n \in \mathbb{N}$

The 12th element of the geometric sequence is: ( $p_{o} = 6$ , $r = 2$ , $n = 12$ )

$p_{12} = 6\cdot 2^{12}$

$p_{12} = 24576$

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2 years ago

What two numbers that if multiplied equal -90 and if added equal 8?

Galina-37 [17]

$x-first\ number\\y-second\ number\\\\ \left \{ {{x\cdot\ y=-90} \atop {x+y=8}} \right.\\\\From\ second\ equayion:\\x=8-y\\\\Substracted\ to\ first\ equation:\\(8-y)y=-90\\-y^2+8y+90=0\\\\\Delta=b^2-4ac\\\Delta=8^2-4\cdot(-1)\cdot90=64+360=424\\\sqrt{\Delta}=\sqrt{424}2\sqrt{106}\\\\y_1=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-8+2\sqrt{106}}{2\cdot(-1)}=4-\sqrt{106}\\y_2=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-8-2\sqrt{106}}{2\cdot(-1)}=4+\sqrt{106}\\\\x_1=8-(4-\sqrt{106})=8-4+\sqrt{106}=4+\sqrt{106}$
$x_2=8-(4-+\sqrt{106})=8-4-\sqrt{106}=4-\sqrt{106}\\\\ \left \{ {{y=4-\sqrt{106}} \atop {x=4+\sqrt{106}}} \right.\\$

3 0

3 years ago

The temperature in degrees Celsius is 273.15 less than the temperature in kelvin. Andrew is conducting a science experiment wher

Stella [2.4K]

Answer:

The whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.

Step-by-step explanation:

The temperature in degrees Celsius is 273.13 less than the temperature in kelvin; mathematically this means:

$k=c+273.15$

Where $k$ is the temperature in kelvin and $c$ is the temperature in Celsius.

From this relationship we convert Andrew's temperature range—

13.5°c to 18.5°c—to kelvin:

$k_1=13.5^oc+273.15=286.65$

$k_2=18.5^oc+273.15=291.65$

Thus Andrew can conduct his experiment between 286.65 and 291.65 kelvin, and the whole number temperatures between these extremes are 287, 288, 289,290,291.

Thus the whole number temperatures, in kelvin, at which Andrew can conduct his experiment are 287, 288, 289,290,291.

3 0

2 years ago