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Andre45 [30]
3 years ago
11

What is the point slope form of the line with slope 25 that passes through the point (−4, −7) ?

Mathematics
1 answer:
ZanzabumX [31]3 years ago
7 0
M=25
x1=-4
y1=-7

y-y1=m(x-x1)
y-(-7)=25(x-(-4))
y+7=25(x+4)
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The lesson of __________ is to forget about the money that’s irretrievably gone and instead to focus on the marginal costs and b
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Answer:sunk costs

Step-by-step explanation:

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2 years ago
What is the area of this face?<br> 12 ft<br> 6ft<br> 6 ft<br> 6 ft
Kitty [74]

Answer:

hi

Step-by-step explanation:

the area of the front face by the width. Vc= 20 cm2 x 10 cm. = 200 cm. Area = 20 cm? 2 ft. The volume of soil in the planter is 36 cubic feet. 6 ft. I draw a rectangular prism and I have a prism with the dimensions of 8 in by 12 in by 20 in.

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3 0
3 years ago
13. What is the result of adding 5.4a + 7.1 and -1.28 - 6.3?
den301095 [7]

Answer:

C. 4.2a + 0.8

Step-by-step explanation:

Given:

The two binomials given for addition are:

5.4a+7.1 and -1.2a-6.3

Now, adding both the binomials, we get:

5.4a+7.1+(-1.2a-6.3)

Distributing the positive sign inside the second binomial, we get:

5.4a+7.1-1.2a-6.3

Now, combining like terms using the commutative property of addition, we get:

(5.4a-1.2a)+(7.1-6.3)

Simplifying the above expression, we get:

(5.4-1.2)a+0.8\\4.2a+0.8

Therefore, the resulting addition of the given binomials is 4.2a+0.8

Hence, option C is the correct answer.

8 0
3 years ago
Give pedro jogs every 4 days and Logan jogs every 6 day and I jog together how many days will it take for them to jog again toge
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Answer:

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Step-by-step explanation:

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7 0
3 years ago
The recursive function LaTeX: f\left(0\right)=1,\:f\left(n\right)=f\left(n-1\right)+2nf ( 0 ) = 1 , f ( n ) = f ( n − 1 ) + 2 n
m_a_m_a [10]

Question:

The recursive function f(0) = 1, f(n) = f(n-1) + 2n represents the nth term of a sequence. Determine the explicit function

Answer:

f(n) = n^2 + n+1

Step-by-step explanation:

Given

f(0) = 1

f(n) = f(n-1) + 2n

Required

Write an explicit formula

Let n = 1

f(1) = f(1-1) + 2*1

f(1) = f(0) + 2

f(1) = 1 + 2 = 3

Let n = 2

f(2) = f(2-1) + 2*2

f(2) = f(1) + 4

f(2) = 3 + 4 = 7

Let n =3

f(3)=f(3-1) + 2 * 3

f(3)=f(2) + 6

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Let n = 4

f(4) = f(4 - 1) + 2 * 4

f(4) = f(3) + 8

f(4) = 13+ 8 = 21

So, we have:

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f(3) = 13= 7 + 2 * 3= 1+2*3+2*3

f(4) = 21 = 13 + 2 * 4= 1+3*4 +2 *4

Following the above pattern:

f(n) = 1 + (n - 1) * n + 2 * n

f(n) = 1 + n(n - 1) + 2n

Open bracket

f(n) = 1 + n^2 - n + 2n

f(n) = 1 + n^2 + n

f(n) = n^2 + n+1

3 0
2 years ago
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