To solve this problem, let us all convert the mass of
each element into number of moles using the formula:
moles = mass / molar mass
Where,
molar mass K = 39.10 g / mol
<span>molar mass Cl = 35.45 g / mol</span>
molar mass O = 16 g / mol
<span>and mass O = 13 g – 4.15 g
– 3.76 g = 5.09 g</span>
moles K = 4.15
g / (39.10 g / mol) = 0.106 mol
<span>moles Cl = 3.76 g / (35.45 g / mol) = 0.106 mol</span>
moles O = 5.09 g / (16 g /
mol) = 0.318 mol
The ratio becomes:
0.106 K: 0.106 Cl: 0.318 O
We divide all numbers with
the smallest number, in this case 0.106. This becomes:
K: Cl: 3O
Therefore the empirical formula
is:
Answer:
gimme that chocky milk.....
Explanation:
Answer is: CaCl₂(s), calcium chloride.
Calcium cations and chlorine anions have a crystal structure in this solid inorganic salt. Ions have <span>the ordered arrangement.</span><span>
Ethane (C</span>₂H₆) is gas, g is chemistry
abbreviations or physical state symbol for gas, gases do not have a crystal structure.
Methanol (CH₃OH) is liquid, l is chemistry abbreviations or physical state symbol for liquids, it do not have a crystal structure.
Calcium iodide is dissolved in water, aqueous solution
(aq) do not have a crystal structure.
The degree of polarity of diatomic molecule is related to the difference of electronegativity of the two atoms. If the difference is very large, i.e. one atom is highly electronegative and the other atom is highly electropostive then, the covalent bond is formed. But if the difference between the electronegativities is very less, then its likely that ionic bond is formed.
Answer:
- <em>The molar concentraion is </em><u>0.74 M</u>
Explanation:
<u>1) Data:</u>
a) % w/v = 2.5%
b) compound: H₂O₂ (from a table molar mass = 34.0147 g/mol)
c) M = ?
<u>2) Formulae:</u>
a) % w/v = (mass of soulte / volume of solution) × 100
b) numer of moles, n = mass in grams / molar mass
c) M = number of moles of solute / liters of solution
<u>3) Solution:</u>
a) T<u>ake a base of 100 ml of solution (0.100 liter)</u>:
- %w/v = 2.5% = 2.5 g solute / 100 ml solution
- mass of solute = 2.5 g / 100 ml × 100 ml = 2.5 g
b) <u>Calculate the number of moles of solute, n</u>:
- n = mass in grams / molar mass = 2.5 g / 34.0147 g/mol = 0.0735 mol
c) <u>Calculate the molarity, M</u>:
- M = n / V in liter = 0.0735 mol / 0.100 liter = 0.735 M
Round to two significant figures: 0.74 M ← answer
