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3 years ago

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Math-- Farmer Bill has 500 meters of fencing and wants to enclose a rectangular plot that borders on a river. If farmer Bill doe

s not fence the side along the river, find the length and width of the plot that will maximize the area. What is largest area that can be enclosed?

1 answer:

bixtya [17]3 years ago

6 0

Answer:

Required dimensions of the rectangle are L = 200 m, W = 100 m

The largest area that can be enclosed is 20,000 sq m.

Step-by-step explanation:

The available length of the fencing = 500 m

Now, Perimeter of a rectangle = SUM OF ALL SIDES = 2(L+B)

But, here once side of the rectangle is NOT FENCED.

So, the required perimeter

= Perimeter of Complete field - Boundary of 1 open side

= 2(L+ W) - L = 2W + L

Now, fencing is given as 500 m

⇒ 2W + L = 500

Now, to maximize the length and width:

put L = 200, W = 100

we get 2(W) +L = 2(200) + 100 = 500 m

Hence, required dimensions of the rectangle are L = 200 m, W = 100 m

The maximized area = Length x Width

= 200 m x 100 m = 20, 000 sq m

Hence, the largest area that can be enclosed is 20,000 sq m.

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Answer:

a

$y(t) = y_o e^{\beta t}$

b

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Step-by-step explanation:

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substituting for y

$\frac{dx}{dt} = - \alpha x(y_o e^{-\beta t })$

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Now integrating both sides

$lnx = \alpha \frac{y_o}{\beta } e^{-\beta t} + c$

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$x(t) = e^{\alpha \frac{y_o}{\beta } e^{-\beta t} + c}$

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3 years ago

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Answer:

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2 years ago

Read 2 more answers

Please help!! 50/25 points!!<br><br> Compute the sum

AfilCa [17]

Answer:

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Step-by-step explanation:

From the question given above, the following data were obtained:

7•2ᶦ

i = 0, 1, 2, .., 8

Sum =?

The sum can be obtained as follow:

7•2ᶦ

i = 0

7•2⁰ = 7 × 1 = 7

i = 1

7•2ᶦ = 7•2¹ = 7 × 2 = 14

i = 2

7•2ᶦ = 7•2² = 7 × 4 = 28

i = 3

7•2ᶦ = 7•2³ = 7 × 8 = 56

i = 4

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i = 5

7•2ᶦ = 7•2⁵ = 7 × 32 = 224

i = 6

7•2ᶦ = 7•2⁶ = 7 × 64 = 448

i = 7

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I hope this helps. :)

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