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Alenkasestr [34]
3 years ago
5

what is the equation in slope intercept form for the line that passes through the points (2,4) and (3,6)

Mathematics
1 answer:
-Dominant- [34]3 years ago
6 0

Answer:

y=2x

Step-by-step explanation:

y=mx+b

m=(6-4)/(3-2)=2

b=y-mx

b=4-(2)(2)

b=4-4

b=0

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2x−4y=20 whats the answer
alexdok [17]

The answer is

x=10+2y

Steps:

2(x-2y)=20

x-2y=20/2 (in fraction form 20/2)

x-2y=10

X=10+2y

4 0
3 years ago
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The scale on a map shows that 200 miles is represen by 5 inches on a map. Which proportion can be used to find the distance on t
Mandarinka [93]

Answer:

1.25 inches

Step-by-step explanation:

200 miles/ 50 miles = 5 inch / x

x = (50 x 5) / 200 = 250 / 200 = 1.25

4 0
3 years ago
M1|L7 1<br> Decimal Round<br> Round 5.489 to the nearest hundredth. )<br> Label the endpoints. )
vagabundo [1.1K]

Answer:

5.49

Step-by-step explanation:

5.48<u>9,</u> the number 9 that is underlined is 5 or more so you put that at 0 then it would be 5.48, but since the 8 is also 5 or more and is the hundreths place you round that to 9 giving you 5.49

3 0
3 years ago
Traders joes sold 7981 bags of tortilla chips recently. If 1178 of these bags were fat free find the percent that were fat free.
lawyer [7]

Answer:

14.76% of tortilla chips bag were fat free.  

Step-by-step explanation:

We are given the following in he question:

Number of bags of tortilla chips sold = 7981

Number of bags hat were fat free = 1178

We have to find the percentage of bags that were fat free.

Percentage:

\dfrac{\text{Number of fat free bags}}{\text{Total number of bags}}\times 100\%\\\\=\dfrac{1178}{7981}\times 100\%\\\\=14.76\%

Thus, 14.76% of tortilla chips bag were fat free.

4 0
3 years ago
If sin(A+B)=1/2 &amp; sin(A-B)=1/3 find sin(2A)
timofeeve [1]

Answer:

sin(2A) = (2√2 + √3) / 6

Step-by-step explanation:

2A = (A+B) + (A−B)

sin(2A) = sin((A+B) + (A−B))

Angle sum formula:

sin(2A) = sin(A+B) cos(A−B) + sin(A−B) cos(A+B)

sin(2A) = 1/2 cos(A−B) + 1/3 cos(A+B)

Pythagorean identity:

sin(2A) = 1/2 √[1 − sin²(A−B)] + 1/3 √[1 − sin²(A+B)]

sin(2A) = 1/2 √(1 − 1/9) + 1/3 √(1 − 1/4)

sin(2A) = 1/2 √(8/9) + 1/3 √(3/4)

sin(2A) = 1/3 √2 + 1/6 √3

sin(2A) = (2√2 + √3) / 6

6 0
3 years ago
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