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padilas [110]
3 years ago
9

Choose the graph that represents the equation y = 2|x – 2|.

Mathematics
1 answer:
mote1985 [20]3 years ago
5 0

Answer:

Step-by-step explanation:

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Evaluate the expression when r = 3.<br> 15r
Liula [17]

Answer:

45

Step-by-step explanation:

Because if you replace the r with 3, it would be 15(3).

15(3) is the same as 15 × 3.

15 × 3 = 45

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8 0
3 years ago
F(x)=2x+1 and g(x)=x^2-7, find (f g) (x)
hodyreva [135]

The answer is (f o g)(x) = 2x^2 - 13

In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).

f(x) = 2x + 1 ----> Remove variable.

f(x) = 2(      ) + 1 ----> Insert g(x)

(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute

(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify

(f o g)(x) = 2x^2 - 13

5 0
3 years ago
A textbook search committee is considering
lora16 [44]

Number of ways to select 3 books from 13 books for adoption is 286 .

<u>Step-by-step explanation:</u>

A Permutation is an ordered Combination. When the order does matter it is a Permutation. There are basically two types of permutation:

  • Repetition is Allowed: such as the lock above. It could be "333".
  • No Repetition: for example the first three people in a running race. You can't be first and second.

Formula is given by:

nC_r= \frac{n!}{r! (n-r)!} , where n is the number of things to choose from,  and we choose r of them,  no repetitions,  order matters. Here , n=13 , r=3.

⇒ 13C_3 = \frac{13!}{3!(13-3)!}

⇒ 13C_3 = \frac{13!}{3!(10)!}

⇒ 13C_3 = \frac{13(12)(11)10!}{3(2)(1)(10)!}

⇒ 13C_3 = 13(2)(11)

⇒ 13 C_3 = 286

∴ Number of ways to select 3 books from 13 books for adoption is 286 .

3 0
3 years ago
14 less than 8 times 8 number is 3 more than four times the number what is the answer​
aliina [53]

Answer:The answer is 11.75

Step-by-step explanation:

5 0
3 years ago
When will the equation p(b)=520(0.88)^b have a value less than 100?
yulyashka [42]

Answer:

The given equation will have value less than 100 whenever the value of b is greater than 12.89

Step-by-step explanation:

For the given equation, p(b) = 520 × 0.88^{b} to have a value less than 100 we can establish inequality as:

                     p(b) < 100

         or,  520 × 0.88^{b} < 100

         or, \frac{520}{520} × 0.88^{b} < \frac{100}{520}

         or, 0.88^{b} < \frac{1}{5.2}

         or, ㏒ ( 0.88^{b} ) < ㏒  (\frac{1}{5.2})

         or, b× ㏒ 0.88 < ㏒  (\frac{1}{5.2})

         or,  \frac{log (\frac{1}{5.2}) }{log (0.88)}   <  b

         or, 12.89 < b

Hence for the equation to have value less than 100, b must be greater than 12.89.

3 0
3 years ago
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