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telo118 [61]
3 years ago
15

Chiyo has a toolbox with the shape below. A rectangular prism with a length of 8 inches, width of 15 inches, and height of 6 inc

hes. A triangular prism with a triangular base with base 8 inches and height 3 inches. The prism has a height of 15 inches. Which statements are true about the toolbox? Select two options. The shape can be broken into a rectangular prism and a triangular prism. The shape can be broken into a rectangular prism and a rectangular pyramid. The formula for the volume of this figure is V = B h + one-third B h. The volume of the toolbox is 840 inches cubed The volume of the toolbox is 900 inches cubed
Mathematics
1 answer:
guajiro [1.7K]3 years ago
3 0

Answer:

Option A and E.

Step-by-step explanation:

It is given that Chiyo has a toolbox with the shape of a rectangular prism with a length of 8 inches, width of 15 inches, and height of 6 inches. A triangular prism with a triangular base with base 8 inches and height 3 inches. The prism has a height of 15 inches.  

The shape can be broken into a rectangular prism and a triangular prism.

So, option A is correct.

Volume of rectangular prism =l\times b\times h

Where, l is length , b is width and h is height.

V_1=8\times 15\times 6=720

Volume of triangular prism =Bh

Where, B is base area and h is height.

Area of triangular base is

B=\dfrac{1}{2}\times 8\times 3=12

So, volume of triangular prism is

V_2=12\times 15

V_2=180

So, volume of tool box is

V=V_1+V_2=720+180=900\text{ inches cubed}

Therefore, the correct option is E.

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What must be true of PQ?
yulyashka [42]
Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong. 

PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.

PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.

The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable). 


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3 years ago
PLEASE HELP QUICK, I need to know the answer.
Marysya12 [62]

The equivalent expression is 7^{2}.

We have the following expression -

\frac{7^{-3} }{7^{-5} }

We have to find its equivalent value.

<h3>What is the equivalent expression of the following expression-</h3>

f(x, y) =\frac{A^{x} }{A^{y} }

In order to divide two exponents with same base, we use the 'Quotient property of exponents.

The equivalent expression can be written as -

f(x, y) = A^{x} A^{-y} = A^{x-y}

In the question given we have -

\frac{7^{-3} }{7^{-5} }

Using the property discussed above -

7^{-3}\;7^{5} = 7^{-3+5} = 7^{2}

Hence, the equivalent expression is 7^{2}.

To solve more questions on exponents, visit the link below -

brainly.com/question/17173276

#SPJ5

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