Suppose a bus arrives at a bus stop every 40 minutes. If you arrive at the bus stop at a random time, what is the probability th
at you will have to wait at least 10 minutes for the bus? Write the probability as a simplified fraction.
plzzzz help hahaha
1 answer:
Answer:
=3/4
Step-by-step explanation:
A bus arrives at a bus stop every 40 minutes.
You arrive at a bus stop at a random time.
So, probability that you will wait at most 10 minutes = 10/40
So, The probability that you will wait at least 10 minutes= 1-10/40
=1- 10/40
By taking L.C.M we get;
=40-10/40
=30/40
=3/4
Thus the probability that you will have to wait at least 20 minutes for the bus is 3/4....
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Step-by-step explanation:
Step-by-step explanation:
The required sum
=(1+2+3+...+199)−(3+6+9+...+198)−(5+10+15+...+195)+(15+30+45+...+195)
=2199(1+199)−266(3+198)−239(5+195)+213(15+195)
=199×100−33×201−39×100+13×105=10732
Step-by-step explanation:
Since, roots are - 3 & 2
Therefore, (x + 3) & (x - 2) would be factors.
Leading coefficient is 5
Hence, required quadratic equation is:
