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2 years ago

Find the GCF of 4y and 12y

Mathematics

1 answer:

love history [14]2 years ago

7 0

Answer:

Step-by-step explanation:

The factors of 4 are: 1, 2, 4

The factors of 12 are: 1, 2, 3, 4, 6, 12

Then the greatest common factor is 4.

Hope this helps! :D

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Can someone help me ? Its due today please

anastassius [24]

Answer:

x=3

y=5

Step-by-step explanation:

3x+2y=19

- 2x+2y=16

_____________

x=3

3(3)=9

19-9=10

10÷2=5

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3 years ago

Read 2 more answers

What is the expression for the calculation double the product of 8 and 3

neonofarm [45]

(8*3)2 is correct answer for your question

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3 years ago

A music company sells music to download, they charge $7.00 for each album and $1.50 for each song. On monday the company sold a

DochEvi [55]

Answer:

1:14

Step-by-step explanation:

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2 years ago

I need help getting the answer for the 1st question

Karo-lina-s [1.5K]

If we have two similar triangles:
Triangle 1 (base 1 , height1).
Triangle 2 (base 2, height 2)
Then:

base 1 /height 1=base 2 /height 2

Data:
base 1=0.2 m
height 1= 1 m
base 2= 8 m
height 2=x

We calculate the height of the tower:
base 1 /height 1=base 2 /height 2
0.2 m / 1m=8 m / x
x=(8 m * 1 m) / 0.2 m
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2 years ago

Suppose you are managing 15 employees, and you need to form three teams to work on different projects. Assume that all employees

Afina-wow [57]

Answer:

There are 17,418,240 different ways to choose the teams.

Step-by-step explanation:

Arrangements of n elements:

The number of possible arrangements of n elements is given by:

$A_{n} = n!$

In how many different ways can the teams be chosen so that the number of employees on each project are as follows: 9, 4, 2?

This is:

Arrangement of 9 elements, followed by an arrangement of 4 elements followed by an arrangement of 2 elements. So

$T = A_{9}*A_{4}*A_{2} = 9!*4!*2! = 362880*24*2 = 17418240$

There are 17,418,240 different ways to choose the teams.

7 0

2 years ago