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elena55 [62]
3 years ago
8

9/35x7/16x20/21 reduce to lowest terms. Convert the answers to mixed numbers where possible

Mathematics
1 answer:
8_murik_8 [283]3 years ago
5 0
The answer is .107 by working left to right
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a store buys CDs with $1 for each and sells them for 1.5 each how many CDs should they sell to earn $100
abruzzese [7]
67 CDS

100/1.5=^
Hope this helps!
6 0
3 years ago
Read 2 more answers
Which ordered pair is a solution of the equation y equals x minus 3
Rom4ik [11]
Y = x-3

Basically you just need to plug in an x value and solve for y
y = x - 3
y = (4) - 3
y = 1

In this case, the ordered pair of this equation would be (4, 1)

You can do this given any x or y coordinate

Hope this helps 
6 0
3 years ago
Cyril has six more than twice as many mangoes as Kubie and half as many mangoes as Maxine. If Kubie has six mangoes, then, in te
sveticcg [70]

Answer:

(7x + 18) or 60 Mangoes

Step-by-step explanation:

Let the no. of mangoes Kubie possesses be x

So,

Cyril has mangoes = 2x + 6  ...(i)

So,

Maxine has = 2 * (2x + 6)

= 4x + 12

Given that,

Kubie has mangoes = 6

∵ The combined mangoes they have in terms of x,

= Cyril + Kubie + Maxine

= (2x + 6) + x + (4x + 12)

= 7x + 18

A.T.Q.

Cyril has = 2x + 6

∵ Cyril has mangoes = 2 * (6) + 6

= 18 mangoes

∵ Maxine has = 2 * Cyril's mangoes

= 2 * 18

= 36

Thus,

Total mangoes = Cyril + Kubie + Maxine

= 18 + 6 + 36

= 60 Mangoes

5 0
3 years ago
CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte
rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt

By definition of absolute value,

|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)

Over this particular integration interval,

• sin(<em>t</em> ) ≥ 0 for 1 ≤ <em>t</em> < <em>π</em>, and

• sin(<em>t</em> ) < 0 for <em>π</em> < <em>t</em> ≤ 5

so you end up splitting the integral at <em>t</em> = <em>π</em> as

\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt

Now compute the distance:

\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5

\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))

\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82

making B the correct answer.

7 0
2 years ago
I have an hour left to finish this exam plz help me qwq"
sergejj [24]

Answer:

B. 10    E. 20   C. 60

Step-by-step explanation:

s = 2f

t = 2(f + s)

(15 + 15 + 30 + f + s + t)/6 = 25       This equation and the equations above show how the variables relate to each other

f = 10               The first number is 10

s = 2(10)=20   The second number is 20

t = 2(10 + 20) = 60   The third number is 60

If these answers are correct, please make me Brainliest!

6 0
3 years ago
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