Answer:
Correct option:
(B) <em>H₀</em>: <em>μ</em> = 2.40 vs. <em>Hₐ</em>: <em>μ</em> ≠ 2.40.
Step-by-step explanation:
The registrar of particular university in 1975 plans to look at records of students graduating last year to see if the mean GPA has changed from 2.40.
The registrar can use a single mean test to determine whether the mean has changed or not.
The hypothesis can be described as:
<em>H₀</em>: The mean GPA is 2.40, i.e. <em>μ</em> = 2.40.
<em>Hₐ</em>: The mean GPA is different from 2.40, i.e. <em>μ</em> ≠ 2.40.
To perform the test the registrar can either use a <em>z</em>-distribution or a <em>t</em>-distribution.
If the data provided gives some insight about the population standard deviation and the sample selected is quite large then the <em>z</em>-distribution can be used.
Otherwise it is wiser to use a <em>t</em>-distribution.
The decision rule is:
If the <em>p</em>-value of the test is less than the significance level then the null hypothesis will be rejected and vice-versa.
Thus, the correct option is (B).
The answer is 24 this needs to be longer so it will send
The frequency table that shows the relative frequency of people older than 40 and don't visit the dentist is:
D. Visit Dentist Yearly Don’t Visit Dentist Yearly
Below 40 0.27 0.73
Above 40 0.57 0.43
<h3>What is the relative frequency required?</h3>
The relative frequency of those older than 40 and don't go annually to a dentist can be found as:
= Number of over 40 who don't go to dentist / Total of those over 40 surveyed
Solving gives:
= 13 / (17 + 13)
= 13 / 30
= 0.43
Find out more on relative frequency at brainly.com/question/16832475.
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Good question , don’t really know but use photo math or there’s an link for you
