Answer:
he played 13,500 games and has 37 percent win rate
The base for a hexadecimal number system is 16
Answer:
2 bytes
Explanation:
Size of the MAR ( memory address register ) = 18 bits = 2 bytes
Given that
address space = 256 K = 2^8
number of address location= 2^8 * 2^10 ( where 1K = 2^10 )
= 2^18
Given the number of address location = 2^18 ;
Hence 18 bits are required to store the address of the instruction
Int Main () dvaunoax o]inxoo jnjn os'i
Explanation: Int Main KIcqvd[uo v[ionon
hxbc ;zzzzzzzzzzzczjHiuhqvzbp;'k
Answer:
Terribly low storage space, limited to mathematics/computing, required entire rooms to use, and low information yield for hours of processing.
Explanation:
