Answer:
hope this helps and do consider giving a brainliest to the ans if it helped.
Explanation:
//program to check if the entered grid is magic square or not
/**c++ standard libraries
*/
#include<bits/stdc++.h>
using namespace std;
/**function to check whether the entered grid is magic square or not
*/
int isMagicSquare(int arr[3][3]){
int i,j,sum=0,sum1=0,rsum,csum;
for(i=0;i<3;i++){
sum+=arr[i][i];
sum1+=arr[i][2-i];
}
if(sum!=sum1){
return 0;
}
for(i=0;i<3;i++){
rsum=0;
csum=0;
for(j=0;j<3;j++){
rsum+=arr[i][j];
csum+=arr[j][i];
}
if(sum!=rsum){
return 0;
}
if(sum!=csum){
return 0;
}
}
return 1;
}
/** main function to get user entries and
* call function
* and print output
*/
int main(){
int i,j,arr[3][3]={0};
for(i=0;i<3;i++){
for(j=0;j<3;j++){
cout<<"Enter the number for row "<<i<<" and column "<<j<<" : ";
cin>>arr[i][j];
}
}
int ret = isMagicSquare(arr);
if(ret==1){
cout<<"This is a Lo Shu magic square"<<endl;
}
else{
cout<<"This is not a Lo Shu magic square"<<endl;
}
return 0;
}
Select the text you want to alter.
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hope this helps
import random
computer_choice = random.choice(["rock", "paper", "scissors"])
user_choice = input("rock, paper, or scissors? ")
if computer_choice == user_choice:
print("It's a draw!")
elif user_choice == "rock" and computer_choice == "scissors":
print("You win!")
elif user_choice == "paper" and computer_choice == "rock":
print("You win!")
elif user_choice == "scissors" and computer_choice == "paper":
print("You win!")
else:
print("The computer wins!")
I wrote my code in python 3.8. I hope this helps.
Answer:Jun 19, 2019 - Additionally, set up a forward untrust certificate for the firewall to ... After setting up the forward trust and forward untrust certificates required for SSL Forward Proxy ... If you do not install the forward trust certificate on client systems, ... Create a Decryption Policy Rule to define traffic for the firewall to decrypt.
WELCOME
Answer:
Building relationships during your career exploration is called <u>networking</u>.