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Advocard [28]
3 years ago
11

Why do justices use precedents in majority opinions and dissents?

Mathematics
1 answer:
Mandarinka [93]3 years ago
5 0
Justices use precedents in majority opinions and dissents in order to show that other cases with similar circumstances came to a similar decision.
You might be interested in
Nina can braid 144 inches of rope in 3 hours find her unit rate round your answer to the nearest thousand
Alex777 [14]

Answer:

48 inches

or

0.8 minutes

Step-by-step explanation:

To find the unit rate of inches per hour, divide 144 by 3.

144÷3=48

You don't need to round because there are no decimals.

To find the time to braid 1 inch, first multiply 3 by 60 (because there are 60 minutes in 1 hour).

3×60=180

Then divide 144 by 180.

144÷180= 0.8

You don't need to round because there are no thousandths.

7 0
3 years ago
Convert the following angle from degrees to radians. Express your answer in simplest form 345 ∘
postnew [5]

well, since we know that there are 180° in π radians, how many degrees will it be in 345°?

\begin{array}{ccll} degrees&radians\\ \cline{1-2} 180&\pi \\ 345&x \end{array}\implies \cfrac{180}{345}~~ = ~~\cfrac{\pi }{x}\implies \cfrac{12}{23}~~ = ~~\cfrac{\pi }{x} \\\\\\ 12x=23\pi \implies x=\cfrac{23\pi }{12}

8 0
2 years ago
What is the derivative of y=tan(arcsin(x))?
Anuta_ua [19.1K]
Hello,

(tg(x))'=1/cos²(x)

(arcsin(x))'=1/√(1-x²)

cos²(arcsin(x))=1-sin²(arcsin(x))=1-x²


(tg(arcsin(x)))'= \dfrac{1}{cos(arcsin(x)))^2} * \dfrac{1}{\sqrt{1-x^2}} \\

=\dfrac{1}{1-sin(arcsin(x))^2}* \dfrac{1}{\sqrt{1-x^2}} \\

= \dfrac{1}{1-x^2} * \dfrac{1}{\sqrt{1-x^2}} \\

\boxed{= \dfrac{\sqrt{1-x^2}}{x^4-2x^2+1}}\\


4 0
3 years ago
What is the probability of getting eiather getting blue or green spinner that is 3/10 green and 1/3 blue
inysia [295]
The probability is 50% or half or 1/2
8 0
3 years ago
Match each power of a power expression with its simplified expression.
VARVARA [1.3K]

Answer:

> (4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = (-4) ^ {-18}

Step-by-step explanation:

We have to expand the powers of each of them:

> (4^6)^{-3} = 4^{(6 * -3)}

          = 4 ^ {-18}

(4^6)^{-3} = \frac{1}{4 ^ {18}}

> (4^{-3})^{-3} = 4 ^ {(-3 * -3)}

  (4^{-3})^{-3} = 4 ^ 9

> (4^0)^{-9} = 4 ^ {(0 * -9)}

  (4^0)^{-9} = 4 ^0

> (-4^{-9})^2 = -4 ^ {( -9 * 2)}

  (-4^{-9})^2 = -4 ^ {-18}

8 0
3 years ago
Read 2 more answers
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