Use the identity
sec^2x = 1 + tan^2 x
- so sec x = sqrt(1 + tan^2 x) then:-
tan x + sqrt( 1 + tan^2 x) = 1
sqrt ( 1 + tan^2 x) = 1 - tan x
1 + tan^2 x = 1 + tan^2x - 2 tan x
0 = -2 tanx
tan x = 0
x = 0, π
π is an extraneous root because sec 180 = -1
So the answer is 0 degrees
When a shape is rotated, it must be rotated around a point.
<em>See attachment for the image of each rotation.</em>
To do this, the top coordinates of the X shape will be transformed using the appropriate rotation rule; the same rule will then be applied to the other parts of the X shape.
The top coordinates of the X shape are:




For 90 degrees counterclockwise rotation, the rule is:

So, we have:




For 180 degrees rotation, the rule is:

So, we have:




For 270 degrees counter rotation, the rule is:

So, we have:




See attachment for the image of each rotation
Read more about rotations at:
brainly.com/question/1571997
The goal of this function is to get a positive value under the square root sign so that the value would not be invalid. Evaluating F(3,1), the value is 1 + <span>sqrt(4-1^2) or equal to 1 + sqrt of 3.</span> In this case, the domain would be x equal to any numbers and the range equal to numbers from -2 ≤ y ≤ 2.