4: (3/4 - 1/2) X 3/5.
You need them all to have the same denominator (bottom number)
The lowest common denominator (LCM) of 2,4 and 5 is 20
4 X 5 = 20
2 X 10 = 20
5 X 4 = 20
Then multiply the top number by the amount you need to multiply the bottom number by to get 20
3 X 5 = 15
1 X 10 = 10
3 X 4 = 12
(3/4 - 1/2) X 3/5. Turns to (15/20 - 10/20) X 12/20.
15 - 10 = 5
5 X 12 = 60
Answer: 60/20
Simplified: Either 3 or 3/1.
If you use the steps above then you should be able to do the rest :D
If you need anymore help, please ask
9514 1404 393
Answer:
10 square units
Step-by-step explanation:
The triangle appears to have a base length (JL) of 4 units, and a height (JL to K) of 5 units. The area formula can be used:
A = (1/2)bh
A = (1/2)(4)(5) = 10
The area of the triangle is 10 square units.
Answer:
it would be decreasing
Step-by-step explanation:
because it is a linear increasing function
for 1 it is going up from 1-6
and 2 it is a function because there isn't any multiples of the x values/ inputs that go to one y value/ output.
Hello from MrBillDoesMath!
Answer:
(1/3) x = (5/6)
Discussion:
I think you are asking for this equation:
(1/3) x = (5/6) => multiply both sides by 3
(1/3) 3 x = (5/6) 3 => as (1/3) *3 = 1
x = 5*3/6
x= 15/6
x = 5/2 = 2.5
Thank you,
MrB
Answer:
Relations B and E do not represent the function.
Step-by-step explanation:
We know that a function is a relation where each input or x-value of the X set has a unique y-value or output of the Y set.
In other words, we can not have duplicated inputs as there should be only 1 output for each input.
If we closely observe relation B, and E i.e.
- B) {(3,4), (4,5), (3,6). (6,7)}
Relation 'B' IS NOT A FUNCTION
Relation B has duplicated or repeated inputs i.e. x = 3 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Relation 'E' IS NOT A FUNCTION
Relation E has duplicated or repeated inputs i.e. x = 4 appears twice times. we can not have duplicated inputs as there should be only 1 output for each input.
Thus, relation B is NOT a function.
Therefore, relations B and E do not represent the function.
