Answer:
The length of a rectangle is 2 feet more than it's width. How do you find the dimensions of the rectangle if its area is 63 square feet?
Step-by-step explanation:
x(x+2) = 63
x^2 + 2x = 63
x^2 + 2x - 63 = 0
Quadratic formula with numbers plugged in: (-2 +or- sqrt(4 - 4* 1 * -63))/2 becomes
-2 +or- sqrt(256)/2 so (-2 +or- 16)/2 therefore -18/2 or 14/2. Discard negative result.
x = 7. 63/7=9. Sides are 7ft and 9ft.
Answer:
6
Step-by-step explanation:
3 × (10 - 6) ÷ 2 =?
The strategy that we are using here is <u>PEMDAS</u>:
First, you subtract 6 <u>from</u> 10 which is 4. <em>10 - 6 =</em><em>4</em>
Next, you <u>multiply</u> 4 by 3. <em>4 × 3 = </em><em>12</em>
Then, you <u>divide</u> 12 by 2. <em>12 ÷ 2 = </em><em>6</em>
Your answer is 6.
Your welcome. Showed my work below.
Answer:
x
=3
t
/m -4y/m
Step-by-step explanation:
Answer:
where is the statements
Step-by-step explanation: