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n200080 [17]
3 years ago
11

2^7-3x=1/4 solve equation

Mathematics
2 answers:
Fofino [41]3 years ago
6 0

Answer:x=

511

12

Step-by-step explanation:

Let's solve your equation step-by-step.

27−3x=

1

4

Step 1: Simplify both sides of the equation.

27−3x=

1

4

128+−3x=

1

4

−3x+128=

1

4

Step 2: Subtract 128 from both sides.

−3x+128−128=

1

4

−128

−3x=

−511

4

Step 3: Divide both sides by -3.

−3x

−3

=

−511

4

−3

x=

511

12

Answer:

x=

511

12

xenn [34]3 years ago
4 0

Answer:

42.583 (3 is repeated)

Step-by-step explanation:

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geniusboy [140]
29 - 29 x 15= 24.65
24.65 + 24.65 x .07= 26.3755 which rounds to 26.38
The answer is $26.38
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Which rule can be used to find the output numbers in this table
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An input-output table, like the one shown below, can be used to represent a function. Each pair of numbers in the table is related by the same function rule. That rule is multiply each input number
6 0
2 years ago
What is the value of tan A?
Ronch [10]

For the given triangle, the tan of angle A equals \frac{3}{4} = 0.75.

Step-by-step explanation:

Step 1:

In the given triangle for angle A, the opposite side has a length of 6 cm, the adjacent side has a length of 8 cm while the hypotenuse of the triangle measures 10 cm. To calculate the tan of angle A we divide the opposite side's length by the adjacent side's length.

tan A = \frac{oppositeside}{adjacent side}.

Step 2:

The opposite side's length = 6 cm.

The adjacent side's length = 8 cm.

tan A = \frac{oppositeside}{adjacent side} = \frac{6}{8} = \frac{3}{4} = 0.75.

6 0
2 years ago
Which line intersects the parabola y = x^2 + 6x-2 at two points?
schepotkina [342]

Answer:

C

Step-by-step explanation:

You find y-intercept x=0

3 0
3 years ago
The length of a photograph is 1 cm less than twice the width. The area is 91cm^2. find the width and length.
maksim [4K]

Answer:

Width=6.5 cm

Length=12 cm

Step-by-step explanation:

Step 1: Express the lengths and widths

Width=w

Length=l, but 1 cm less than twice the width=(2×w)-1=2 w-1

Step 2: Solve for the length and width

A=L×W

where;

A=area of the photograph

L=length of the photograph

W=width of the photograph

In our case;

A=91 cm²

L=2 w-1

W=w

91=(2 w-1)w

2 w²-w=91

2 w²-w-91=0, is a quadratic equation

solve for w

w={-1±√(-1²-4×2×-91)}/(2×2)

w=(-1±27)/4

w=(27-1)/4=6.5, or (-1-27)/4=-8

Take w=6.5 cm

L=(2×6.5)-1=13-1=12 cm

Width=6.5 cm

Length=12 cm

6 0
3 years ago
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