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Lena [83]
3 years ago
7

3.1 Q19

Mathematics
1 answer:
IgorC [24]3 years ago
5 0
Let one length be x and the other be y

x + x + y + y = 440
2x + 2y = 440

Divide by 2 through ...
x + y = 220
y = 220 - x

Area = xy
Area = x(220 -x) = 220x - x^{2}

Given that that max length of x will be -b/2a
a = -1 b = 220
x = \frac{-220}{-2} = 110

x = 110
y = 220 - 110 = 110

Therefore max area = 110 x 110 = 12100 square yards


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Answer:

The lines are parallel with an acute angle of 0 degrees.

Missing Information:

The equations of lines are missing which are as follows:

<u>Line 1:</u>

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<u>Line 2:</u>

x = 2 + 4s , y = -1 -2s, z = 3

Step-by-step explanation:

First, we need to find the direction vectors of both the line, we can write them as:

Direction Vector of line 1 =D_{1}= -2u + 1v + 0w

Direction Vector of line 2= D_{2}=4u -2v+0w

As we can see,

D_{2}=-2 D_{1}

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4u -2v+0w= -2(-2u + 1v + 0w)

Since,

D_{2}=-2 D_{1}

So the lines are parallel such that<u> θ= 0 degrees.</u> (Which is the acute angle between them)

All the points on line 1 have z-coordinate as 5 (z=5),

All the points on line 2 have z-coordinate as 3 (z=3),

Since the z-coordinate do not match , so the lines are not coincident.

Also as the lines are parallel so they are not intersecting.

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<h3>What is fixed rate?</h3>

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