Solution-
First 9 letters of alphabet are- A,B,C,D,E,F,G,H,I
Total number of ways of selection of 4 letters from 9 alphabets = 9C4
=9!÷((4!).(9-4)!) = 9!÷(4!×5!) = (9×8×7×6)÷(24) = 126
The number of ways of arranging these 4 numbers = 4! = 24
∴ Total number of possible permutations = 9C4×4! = 126×24 = 3024
∴ option number 2 is correct.
Answer:
1 1/8
Step-by-step explanation:
3/8+ 3/8= 6/8+3/8=1 1/8
Answer:
60m²
Step-by-step explanation:
my dude you need to know this. A=bh. A=10(6).
Answer:
About 2.37
Step-by-step explanation:
Answer:
10000000
Step-by-step explanation: