Ok, here we go. Pay attention. The formula for the arc length is

. That means that to use that formula we have to find the derivative of the function and square it. Our function is y = 4x-5, so y'=4. Our formula now, filled in accordingly, is

(that 1 is supposed to be negative; not sure if it is til I post the final answer). After the simplification we have the integral from -1 to 2 of

. Integrating that we have

from -1 to 2.

gives us

. Now we need to do the distance formula with this. But we need 2 coordinates for that. Our bounds are x=-1 and x=2. We will fill those x values in to the function and solve for y. When x = -1, y=4(-1)-5 and y = -9. So the point is (-1, -9). Doing the same with x = 2, y=4(2)-5 and y = 3. So the point is (2, 3). Use those in the distance formula accordingly:

which simplifies to

. The square root of 153 can be simplified into the square root of 9*17. Pulling out the perfect square of 9 as a 3 leaves us with

. And there you go!
3/2 = 2q
q = 3/2 ÷ 2
q = 3/2 × 1/2
q = 3/4
Answer:
C seems right to me
Step-by-step explanation:
Answer:
The correct answer is option (C)-0.245 = 2.160(0.205)
Step-by-step explanation:
Solution
Given that:
The slope = - 0.245
The size sample = n = 15
The standard error = 0.205
The confidence level = 95
The Significance level= α = (100- 95)% = 0.05
Now,
The freedom of degree = n-2 = 15 -2= 13
Thus,
the critical value = t* = 2.16
By applying Excel = [TINV (0.05, 13)]
The Margin of error is = t* (standard error)
=2.16 *0.205
= 0.4428
Answer:
Two points on the graph would be (2,-1) and (4,2).
Step-by-step explanation:
You can choose two random x variables such as how i selected 2 and 4. if you change the variable x to those values you can solve for y or in this case f(x).
EX:
3/2*2-4
6/2-4
3-4
f(x)= -1