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Karolina [17]
3 years ago
8

what is the slope intercept form of the linear equation with a graph that passes through (-2,2) and is perpendicular to the grap

h of y=1/3x+9
Mathematics
1 answer:
qwelly [4]3 years ago
7 0

Hey there!!

Steps to get into equation which is perpendicular:

  • Change the slope
  1. The slope of a perpendicular line is always negative reciprocal.
  • Take the point and get that into point-slope form.
  1. y - y = m ( x - x )
  • Convert this equation into slope-intercept form.

'm' is the slope.

We have the slope as 1/3

The perpendicular slope would be -3.

Point slope:

The point = (-2,2)

y - 2 = -3( x - (-2) )

y - 2 = -3(x+2)

y - 2 = -3x -6

Adding 2 on both sides:

y = -3x - 4

<em>Hence, the equation would be : </em>

<u><em>y = -3x - 4 </em></u>

Hope it helps!


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