The equation of a circle with radius r and center at point (a, b) is given by
(x - a)^2 + (y - b)^2 = r^2
1.) For the circle given by x^2 + y^2 = 24
(x - 0)^2 + (y - 0)^2 = (√24)^2
Therefore, center = (0, 0) and radius = √24 = 4.9 units
3.) x^2 + y^2 -10x -2y = -10
x^2 - 10x + (-5)^2 + y^2 - 2y + (-1)^2 = -10 + (-5)^2 + (-1)^2
x^2 - 10x + 25 + y^2 - 2y + 1 = -10 + 25 + 1
(x - 5)^2 + (y - 1)^2 = 16
(x - 5)^2 + (y - 1)^2 = 4^2
We need to write the linear equation that is satisfied by (20,13) and (30,18).
$18 - $13 $5
The slope is m = --------------- = -------- = $0.50/mile
30 - 20 10
We need to find the y-intercept of this function. To do that, start with the slope-intercept form y = mx + b
and subst. the y and x values from one of the two given points. Suppose we choose (20,$13):
$13 = ($0.50/mile)(20 miles) + b
Then $13 = $10 + b, and b = $3.
There's an up-front charge of $3 just to step into the taxi.
The equation in question is y = ($0.50/mile)x + $3.00 (answer)
The formula for the area of a triangle is 1/2(base×height)
30×27=810
810×1/2=405
You would multiply 36 and 6 to get x
